Chapter 39: Q 1 Exercise (page 1136)

An experiment has four possible outcomes, labeled A to D. The probability of A is PA= 40% and of B is PB = 30%. Outcome C is twice as probable as outcome D. What are the probabilities PCand PD?

Short Answer

Expert verified

Therefore the probabilities are:

PD=0.1PC=0.2

Step by step solution

01

Given information

An experiment has four possible outcomes, labeled A to D. The probability of A is PA= 40% and of B is PB = 30%. Outcome C is twice as probable as outcome D.

02

Explanation

The most crucial principle in this problem is that all conceivable outcomes' probability must add up to 1, or 100%. As a result, utilising the information provided in the problem, we can develop two equations.

PC=2PD(1)PA+PB+PC+PD=10.40+0.30+PC+PD=1PC+PD=0.3(2)

Solving (1) with (2)

role="math" localid="1648583743410" 3PD=0.3PD=0.1PC=0.2

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