Chapter 39: Q 9 Exercise (page 1136)

When 5 X 1012 photons pass through an experimental apparatus, 2.0 X 109 land in a 0.10-mm-wide strip. What is the probability density at this point?

Short Answer

Expert verified

Thus, the probability density is4m-1

Step by step solution

01

Given information

When 5 X 1012 photons pass through an experimental apparatus, 2.0 X 109 land in a 0.10-mm-wide strip.

02

Explanation

The probability will be:

P=2.0×1095×1012P=0.0004

Therefore, the probability density is:

P(x)=PδxP(x)=0.00040.10×10-3P(x)=4m-1

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