Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 33: Q. 1 (page 955)

A double slit is illuminated simultaneously with orange light of wavelength 620nm and light of an unknown wavelength. The m=4 bright fringe of the unknown wavelength overlaps the m=3 bright orange fringe. What is the unknown wavelength?

Short Answer

Expert verified

Unknown wavelength is465nm.

Step by step solution

01

Formula for position

The aim is to require use of very fact that the m=4bright orange fringe has the identical position ybecause m=3bright orange fringe.

And we know that for the sunshine fringes within the double slit experiment, we may write the position as follows:

ym=mλLd

02

Calculation for unknown wavelength

We'll ask the unknown wavelength as λun.

And therefore the orange wavelength as λor.

When the positions of the two fringes are equalized, the result is

localid="1649168675266" 4λunLd=3λorLd

Becauselocalid="1649168679741" dandlocalid="1649168685122" Lare equal, they wipe out on equal sides. Hence

localid="1649167746395" λun=3λor4

=3×620nm4

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Optical computers require microscopic optical switches to turn signals on and off. One device for doing so, which can be implemented in an integrated circuit, is the Mach-Zender interferometer seen in FIGURE. Light from an on-chip infrared laser (λ=1.000μm)is split into two waves that travel equal distances around the arms of the interferometer. One arm passes through an electro-optic crystal, a transparent material that can change its index of refraction in response to an applied voltage. Suppose both arms are exactly the same length and the crystal’s index of refraction with no applied voltage is1.522.

a. With no voltage applied, is the output bright (switch closed, optical signal passing through) or dark (switch open, no signal)? Explain.

b. What is the first index of refraction of the electro-optic crystal larger than 1.522that changes the optical switch to the state opposite the state you found in part a?

White light400-700nmincident on a 600line/mmdiffraction grating produces rainbows of diffracted light. What is the width of the first-order rainbow on a screen 2.0mbehind the grating?

Light of wavelength550nm illuminates a double slit, and the interference pattern is observed on a screen. At the position of the m=2 bright fringe, how much farther is it to the more distant slit than to the nearer slit?

Light from a helium-neon laser (λ=633nm) is incident on a single slit. What is the largest slit width for which there are no minima in the diffraction pattern?

FIGURE P33.56 shows the light intensity on a screen behind a single slit. The slit width is 0.20mmand the screen is 1.5mbehind the slit. What is the wavelength (in nm) of the light?

See all solutions

Recommended explanations on Physics Textbooks

Torque and Rotational Motion

Read Explanation

Wave Optics

Read Explanation

Magnetism and Electromagnetic Induction

Read Explanation

Measurements

Read Explanation

Further Mechanics and Thermal Physics

Read Explanation

Conservation of Energy and Momentum

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free