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Chapter 33: Q. 15 (page 955)

In a single-slit experiment, the slit width is 200 times the wavelength of the light. What is the width (inmm)of the central maximum on a screen 2.0m behind the slit?

Short Answer

Expert verified

Width of the central maximum is20mm.

Step by step solution

01

Formula for width

The centre maximum is equal to the distance between the first order minima on both sides of the screen, and it is placed between the minima.

Width of center maximum is2Da.

Angular width of central maximum is2θ=2λa.

So,

w=2λLa

02

Calculation for width

The breadth of the centre maximum is computed as follows:

w=2λLa

=2Lλ200λ

=L100

Width is,

w=2100

=0.02m

=20mm

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Most popular questions from this chapter

A Michelson interferometer using 800nm light is adjusted to have a bright central spot. One mirror is then moved 200nm forward, the other 200nm back. Afterward, is the central spot bright, dark, or in between? Explain.

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FIGURE Q33.1 shows light waves passing through two closely spaced, narrow slits. The graph shows the intensity of light on a screen behind the slits. Reproduce these graph axes, including the zero and the tick marks locating the double-slit fringes, then draw a graph to show how the light-intensity pattern will appear if the right slit is blocked, allowing light to go through only the left slit. Explain your reasoning.
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