Chapter 33: Q. 18 (page 955)

A $0.50 - mm$ -wide slit is illuminated by light of wavelength $500 nm$ . What is the width $(in mm)$ of the central maximum on a screen $2.0 m$ behind the slit $?$

Short Answer

Expert verified

Width of the central maximum is $4 mm$ .

Step by step solution

Formula for width

The focus maximum is equal to the distance between the first order minima along both sides of the screen, yet it is positioned between the minima.

$2 Da$ is the maximum width of the centre.

$2 θ = 2 λa$ is the centre maximum's angular width.

$w = \frac{2 λL}{a}$

Calculation for width

The width of the median maximum in the scientific experiment is

$w = \frac{2 λL}{a}$

This width will be in our case

localid="1649240628379" $w = \frac{2 \times 5 \times 10^{- 7} \times 2}{5 \times 10^{- 4}}$

$= 4 \times 10^{- 3} m$

$= 4 mm$

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A $0.50 - mm$ -wide slit is illuminated by light of wavelength $500 nm$ . What is the width $(in mm)$ of the central maximum on a screen $2.0 m$ behind the slit $?$

Short Answer

Step by step solution

Formula for width

Calculation for width

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A 0.50-mm-wide slit is illuminated by light of wavelength 500nm. What is the width (inmm)of the central maximum on a screen2.0mbehind the slit?

Short Answer

Step by step solution

Formula for width

Calculation for width

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Magnetism and Electromagnetic Induction

Work Energy and Power

Turning Points in Physics

Circular Motion and Gravitation

Wave Optics

Fluids

Study anywhere. Anytime. Across all devices.

A $0.50 - mm$ -wide slit is illuminated by light of wavelength $500 nm$ . What is the width $(in mm)$ of the central maximum on a screen $2.0 m$ behind the slit $?$