Chapter 33: Q. 25 (page 956)

A $0.50 - m m$ -diameter hole is illuminated by light of wavelength $550 n m$ . What is the width (in mm) of the central maximum on a screen $2.0 m$ behind the slit?

Short Answer

Expert verified

The Width of the cental screen is $4.8 m m$

Step by step solution

Introduction

When light passes through a narrow opening, such as an aperture with a low f-number, it causes lens diffraction, which is an optical interference.

When the wavelength of light and the size of the opening are about the same, lens diffraction occurs.

Find width

In a circular-aperture experiment, the central width is given by

$w = \frac{2.44 λ L}{D}$

where $D$ is the aperture diameter and $L$ is the distance to the screen

Find width

In our scenario, we'll be able to

$w = \frac{2.44 λ L}{D}$

localid="1650215942766" $w = \frac{2.44 \times 5 \times 10^{- 7} m \times 2 m}{5 \times 10^{- 4} m}$

$= 4.88 \times 10^{- 3} m$

$= 4.88 mm$

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A $0.50 - m m$ -diameter hole is illuminated by light of wavelength $550 n m$ . What is the width (in mm) of the central maximum on a screen $2.0 m$ behind the slit?

Short Answer

Step by step solution

Introduction

Find width

Find width

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A 0.50-mm-diameter hole is illuminated by light of wavelength 550nm. What is the width (in mm) of the central maximum on a screen 2.0m behind the slit?

Short Answer

Step by step solution

Introduction

Find width

Find width

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Medical Physics

Scientific Method Physics

Space Physics

Dynamics

Engineering Physics

Radiation

Study anywhere. Anytime. Across all devices.

A $0.50 - m m$ -diameter hole is illuminated by light of wavelength $550 n m$ . What is the width (in mm) of the central maximum on a screen $2.0 m$ behind the slit?