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Chapter 33: Q. 29 (page 956)

Light from a helium-neon laser (λ=633nm)passes through a circular aperture and is observed on a screen 4.0mbehind the aperture. The width of the central maximum is2.5cm. What is the diameter (in mm) of the hole?

Short Answer

Expert verified

Diameter of the hole , D=0.25mm

Step by step solution

01

Helium-neon Laser

Because they're affordable and provides a relentless, visible output, helium-neon (He-Ne) lasers are commonly utilized for interferometry.

They typically work a wavelength of 633nm, however customized versions with useable outputs at other visible and infrared wavelengths are available.

02

Find Distance 

In the circular-slit experiment, the formula for the width of the central fringe is

w=2.44λLD

We find diameter value using the above expression,

D=2.44λLw

03

Find Distance 

Distance is,

D=2.44λLw
D=2.44×6.33×10-7m×4m2.5×10-2m

=2.47×10-4m

=0.25mm

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Most popular questions from this chapter

FIGUREP33.49shows the interference pattern on a screen 1.0mbehind an 800line/mmdiffraction grating. What is the wavelength (in mm) of the light?

A student performing a double-slit experiment is using a green laser with a wavelength of 530nm.. She is confused when the m=5maximum does not appear. She had predicted that this bright fringe would be 1.6cmfrom the central maximum on a screen 1.5mbehind the slits.

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