For your science fair project you need to design a diffraction grating that will disperse the visible spectrum 400-700nmover30.0 in first order.
a How many lines per millimeter does your grating need?
bWhat is the first-order diffraction angle of light from a sodium lamp λ=589nm?

Short Answer

Expert verified

Part a

aThe lines per mm needed for grating isn=1231.

Part b

bThe angle of light from sodium lamp isθ1=46.5.

Step by step solution

01

Step: 1 Equating equation: (part a)

In diffraction grating,has

dsinθ1=λ

The small angle at each wavelength as

localid="1649135282502" dsin(θ)=400nmdsinθ+30=700nmsin(θ)sinθ+30=47sin(θ)=47sinθ+30

02

Step: 2 Finding angle: (part a)

By trignomentry,

sin(a+b)=sinacosb+cosasinb74sinθ=sinθcos30+cosθsin3074sinθ=32sinθ+cosθ27432sinθ=cosθ20.884sinθ=cosθ2sinθcosθ=tanθ=12×0.884θ=tan112×0.884θ=29.5.

03

Step: 3 Calculating numbers: (part a)

Calculating distance and numbers by

d=400nmsin29.5d=812.3nmd=812.3×106mm.n=1812.3×106mmn=1231.

04

Step: 4 Angle of light in sodium lamp: (part b) 

The angle of fringe for any wavelength

sinθ1=λdθ1=sin1λdθ1=sin1589nm812.3nmθ1=46.5.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Light of wavelength 600nmpasses though two slits separated by 0.20mmand is observed on a screen 1.0mbehind the slits. The location of the central maximum is marked on the screen and labeled y=0.

a. At what distance, on either side of y=0, are the m=1bright fringes?

b. A very thin piece of glass is then placed in one slit. Because light travels slower in glass than in air, the wave passing through the glass is delayed by 5.0×10-16sin comparison to the wave going through the other slit. What fraction of the period of the light wave is this delay?

c. With the glass in place, what is the phase difference Δϕ0between the two waves as they leave the slits?2

d. The glass causes the interference fringe pattern on the screen to shift sideways. Which way does the central maximum move (toward or away from the slit with the glass) and by how far?

A double-slit experiment is set up using a helium-neon laser (λ=633nm). Then a very thin piece of glass (n=1.50) is placed over one of the slits. Afterward, the central point on the screen is occupied by what had been the m=10 dark fringe. How thick is the glass?

a. Green light shines through a 100-mm-diameter hole and is observed on a screen. If the hole diameter is increased by 20%, does the circular spot of light on the screen decrease in diameter, increase in diameter, or stay the same? Explain.

b. Green light shines through a 100μm-diameter hole and is observed on a screen. If the hole diameter is increased by20%, does the circular spot of light on the screen decrease in diameter, increase in diameter, or stay the same? Explain.

Light from a helium-neon laser (λ=633nm)passes through a circular aperture and is observed on a screen 4.0mbehind the aperture. The width of the central maximum is2.5cm. What is the diameter (in mm) of the hole?

A double-slit experiment is performed with light of wavelength630nm. The bright interference fringes are spaced 1.8mm apart on the viewing screen. What will the fringe spacing be if the light is changed to a wavelength of 420nm ?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free