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Chapter 9: Q. 18 (page 228)

The two ropes are used to lower a 255 kg piano 5.00 m from a second-story window to the ground. How much work is done by each of the three forces?

Short Answer

Expert verified

$\vec{F_{G}} = 2.00 \times 10^{4} J$

$\vec{T_{1}} = - 1.27 \times 10^{4} J$

$\vec{T_{2}} = - 7.326 \times 10^{4} J$

Step by step solution

01

Step 1. Given Information

We have, $W = Fdcos (θ)$

The work done by all the ropes by

$\vec{F_{G}} = 2500 \times 8 \times \cos (0 °) \vec{F_{G}} = 20000 J \vec{F_{G}} = 2.00 \times 10^{4} J$

For $\vec{T_{1}}$ ,

$\vec{T_{1}} = 1830 \times 8 \times \cos (150 °) \vec{T_{1}} = 14640 \times - 0.866 \vec{T_{1}} = - 1.27 \times 10^{4} J$

And for $\vec{T_{2}}$ ,

$\vec{T_{2}} = 1295 \times 8 \times \cos (135 °) \vec{T_{1}} = 10360 \times - 0.99 \vec{T_{1}} = - 7.326 \times 10^{4} J$

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Most popular questions from this chapter

A $35$ -cm-long vertical spring has one end fixed on the floor. Placing a $2.2$ kg physics textbook on the spring compresses it to a length of $29$ cm. What is the spring constant?

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Evaluate the dot product $\vec{A} \cdot \vec{B}$ if

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b). $\vec{A} = 3 \hat{i} - 2 \hat{j}$ and $\vec{B} = 6 \hat{i} + 4 \hat{j}$

See all solutions

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