One mole (6.02×1023atoms) of helium atoms in the gas phase has 3700J of microscopic kinetic energy at room temperature. If we assume that all atoms move with the same speed, what is that speed? The mass of a helium atom is6.68×10-27 kg.

Short Answer

Expert verified

The speed is 1360m/s

Step by step solution

01

Step 1. Given Information

One mole of helium 6.022×1023

Mass of helium role="math" localid="1647905537418" 6.68×10-27

Kinetic Energy3700J

02

Step 2. One mole of helium atom have mass

monemoleofhelium=Nmoneatomofhelium=6.022·1023·6.68·1027kg=4·10-3kg

03

Step 3. Find the speed 

If that mole of helium atoms have kinetic energy 3700J and they all move at the same speed, we can easily get their speed

Ekinetic=12monemoleofheliumv23700:J=0.5·4·10-3kg·v2v=1360m/s

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