Chapter 9: Q. 32 (page 229)

A $55$ kg softball player slides into second base, generating $950$ J of thermal energy in her legs and the ground. How fast was she running?

Short Answer

Expert verified

Speed of the player is $5.87$ m/s

Step by step solution

Step 1. Kinetic to Thermal energy

The frictional force is generated because of sliding; it's a dissipative force that converts themechanical energy to thermal energy.
$Δ K = - Δ E_{t h}$
Here $Δ E_{t h}$ is that the thermal energy generated and $ΔK$ is change inmechanical energy.

Step 2. Find the velocity

Consider the above formula,
$\begin{aligned} Δ K = - Δ E_{th} \end{aligned}$

$\begin{array}{r} \frac{1}{2} m (v_{f}^{2} - v_{i}^{2}) = - Δ E_{th} \end{array}$

$(v_{f}^{2} - v_{i}^{2}) = \frac{- 2 Δ E_{th}}{m}$

Here

v_{i}^{}

is that the initial speed,

v_{f}^{}

is that the final speed and

m

is that the mass of player.
Substitute

0 m / s

for

v_{f} . 950 J

for

Δ E_{a}

and

55 kg

for

m

$\begin{aligned} v_{i} = \sqrt{\frac{2 (950 J)}{55 kg}} \end{aligned}$

$= 5.9 m / s$

Therefore, the initial speed of the player was

= 5.9 m / s

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A $55$ kg softball player slides into second base, generating $950$ J of thermal energy in her legs and the ground. How fast was she running?

Short Answer

Step by step solution

Step 1. Kinetic to Thermal energy

Step 2. Find the velocity

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A 55 kg softball player slides into second base, generating 950 J of thermal energy in her legs and the ground. How fast was she running?

Short Answer

Step by step solution

Step 1. Kinetic to Thermal energy

Step 2. Find the velocity

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Astrophysics

Medical Physics

Fundamentals of Physics

Engineering Physics

Torque and Rotational Motion

Physics of Motion

Study anywhere. Anytime. Across all devices.

A $55$ kg softball player slides into second base, generating $950$ J of thermal energy in her legs and the ground. How fast was she running?