A 50kg sprinter, starting from rest, runs 50m in 7.0s at constant acceleration.

a. What is the magnitude of the horizontal force acting on the sprinter?

b. What is the sprinter’s power output at 2.0s, 4.0s, and6.0 s?

Short Answer

Expert verified

a). Horizontal force is 102.04 N

b). Out power at t=2 s is 416.32 W, at t=4 s is 832.64 W and at t=6 s is 1284.96 W

Step by step solution

01

Step 1. Given Information

We have,

Mass m=50kg

s=50m in 7.0 s at constant acceleration

02

Step 2. Find the acceleration

Magnitude of force can be found second Newton's law F=ma

Acceleration of sprinter can be found form equation from kinematics that connects distance, time and constant acceleration

s=12at2a=2st2a=2·50m(7s)2a=2.04m/s2

03

Step 3. Part a). Find the magnitude of force

So,

F=maF=50kg·2.04m/s2F=102.04N

04

Part b). Find the sprinter output power

Output power can be found from P=Fv

Pt=2s=102.04N·2.04m/s2·2s=416.32WPt=4s=102.04N·2.04m/s2·6s=832.64WPt=6s=102.04N·2.04m/s2·6s=1248.96W

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