Chapter 9: Q. 47 (page 229)

A ball shot straight up with kinetic energy $K_{0}$ reaches height $h$ . What height will it reach if the initial kinetic energy is doubled?

Short Answer

Expert verified

It the initial kinetic energy is doubled then the height is also doubled

Step by step solution

Work done

Work done by a net force is equals to the change within the mechanical energy.
$W_{net} = Δ K$
Here $W_{net}$ is that the work done by the web force and $∆ K$ is change inmechanical energy.

Mechanical Energy

At the very best point, the full mechanical energy get converted into gravitationalP.E.,
$\begin{aligned} U = K_{0} \end{aligned}$

$\begin{array}{r} m g = K_{0} \end{array}$

h = \frac{K_{0}}{m g}

If themechanical energy is doubled, the corresponding height is calculated as follows,

\begin{aligned} U_{2} = 2 K_{0} \end{aligned}

$\begin{array}{r} m g h_{2} = 2 K_{0} \end{array}$

$h_{2} = \frac{2 K_{0}}{m g}$

$\begin{aligned} h_{2} = \frac{2 K_{0}}{m g} \end{aligned}$

$= 2 h$

Therefore, if mechanical energy is doubled the peak are going to be doubled.

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A ball shot straight up with kinetic energy $K_{0}$ reaches height $h$ . What height will it reach if the initial kinetic energy is doubled?

Short Answer

Step by step solution

Work done

Mechanical Energy

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A ball shot straight up with kinetic energy K0 reaches height h. What height will it reach if the initial kinetic energy is doubled?

Short Answer

Step by step solution

Work done

Mechanical Energy

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Medical Physics

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Study anywhere. Anytime. Across all devices.

A ball shot straight up with kinetic energy $K_{0}$ reaches height $h$ . What height will it reach if the initial kinetic energy is doubled?