The force acting on a particle is Fx=F0e-x/L . How much work does this force do as the particle moves along the x-axis from x=0 to x=L?

Short Answer

Expert verified

The work done on the particle as it moves fromx=0tox=LisF0L(1-1e).

Step by step solution

01

Content Introduction

The work done by the force Fxon the particle if the movement of particle is in same direction as of the force can be expressed as:

W=xixfFxdx

Here, Fxis the force and dxis the small displacement in the direction of the force.

02

Content Explanation

The work done on the particle as it moves from x=0tox=Lis shown as follow:

role="math" localid="1647794367778" W=0LFxdxW=0LF0e-x/LdxW=F0(-Le-x/L)L0 W=F0L(1-1e)

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