In Problems 67 through 69 you are given the equation(s) used to solve a problem. For each of these, you are to

a. Write a realistic problem for which this is the correct equation(s).

b. Draw a pictorial representation.

c. Finish the solution of the problem

Fpush-(0.20)(30kg)(9.8m/s2)=075W=Fpushv

Short Answer

Expert verified

a. The mass is 20kg, the coefficient of kinetic friction isrole="math" localid="1647861976929" 0.15.

b. The pictorial presentation is as follow:

c. The velocity is 6.3m/s.

Step by step solution

01

Content Introduction

Mass is a fundamental feature of all matter, and mass is a quantitative measure of it. A force is a push or pull on an object caused by the interaction of the thing with another object.

02

Explanation (Part a)

The mass is 20kg,the coefficient of kinetic force isrole="math" localid="1647861968818" 0.15.

03

Explanation (Part b)

The pictorial presentation is as follow:

04

Explanation (Part c)

The velocity is calculated as follow:

12[(20kg)v12+0_(0.15)(20kg)(9.8m/s2)cos40°2.5msin40°]=0+(20kg)(9.8m/s2)(2.5m)+0v12=40.2m2/s2v1=6.3m/s

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