A 65cm3 block of iron is removed from an8000C furnace and

immediately dropped into 200 mL of 200C water. What fraction

of the water boils away?

Short Answer

Expert verified

The iron block in this example provided energy to the water until it reached its phase shift. The leftover energy then converted a portion of the water to steam until the system reached equilibrium.

Step by step solution

01

Given information

Given:

We have 65cm3of iron at 800°C,200mLof water at 20°C.

Formula used:

role="math" localid="1650517403634" mironΔCp,ironΔTi,iron+mwaterΔCp,waterΔTi,water=mironΔCp,ironΔTf+mwaterΔCp,waterΔTf+msteamΔCsteam

02

Simplification

Let us solve themsteam

mironΔCp,ironΔTi,iron+mwaterΔCp,waterΔTi,water-mironΔCp,ironΔTf-mwaterΔCwaterΔTf=msteamΔCpsteam

miron=65cm3Δ7.874gcm3=511.81[g]mwater=200[mL]Δ1gmL=200[g]Cp,water=4.181JgΔKCp,iron=0.450JgΔK

Latent heat to vaporize water:

Csteam=2257JgTi,water=20.0C+273.15=293.15[K]Ti,iron=800C+273.15=1073.15[K]Tf=100.0C+273.15=373.15[K]

msteam=511.81[g]Δ0.45JgAKΔ(1073.15[K]-373.15[K])+200|g|Δ4.181JgAKΔ(293.15[K]-373.15[K])2257JKmsteam=41.79[g]x=mstaiamvatir=41.79g]200g]=0.209=20.9%

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