The volume of a gas is halved during an adiabatic compression that increases the pressure by a factor of 2.5.

a. What is the specific heat ratio g?

b. By what factor does the temperature increase?

Short Answer

Expert verified

The answer for (a) is1.90Land (b) is74°C.

Step by step solution

01

Description 

As per provided information, the volume of a gas is halved during an adiabatic compression that increases the pressure by a factor of 2.5.

On the basis of adiabatic process, it can be written as:

p1V2γ=p2V2γ

02

Result on finding the heat ratio g and temperature 

On the basis of adiabatic process, it can be written as:

p1V2γ=p2V2γ

On the basis of second volume:

(V2V1)γ=p1p2V1V2=p1p2γ

Therefore,

V2=V1p1p2γ

On the basis of ideal gas law and numerically

V2=0.1·8.314·4233.10130021.40=1.90L

Thus, as per the ideal gas law when mole number is constant:

p1V1T1=p2V2T2

Therefore, the temperature is on the basis of numerics:

T2=1221.4·423=347K

On the basis of Celcius:

347K=347-273=74°C

Therefore, the answer for (a) is 1.90Land (b) is 74°C.

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