|| A 10 m×14 m house is built on a 12-cm-thick concrete slab.

What is the heat-loss rate through the slab if the ground temperature

is 5°C while the interior of the house is 22°C?

Short Answer

Expert verified

The power needed is 15.9 kW

Step by step solution

01

Formula to use in this problem

For thermal conduction,

dQdt=kALT,

where dQ is the heat transferred in dt and dt is the time differential. If the time difference is unit,P=dQdt

02

Rearrangement of the equation and finding of the power needed

As our surface is rectangular, A=ab, where a and b are the dimensions of the floor. So,

P=kabTL=0.8·10·14·(22-5)0.12=1.59·104=15.9kW

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