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Chapter 19: Q. 47 (page 545)

Your 300 mL cup of coffee is too hot to drink when served at 90°C. What is the mass of an ice cube, taken from a -20°C freezer, that will cool your coffee to a pleasant 60°C?

Short Answer

Expert verified

The mass is 60.2g

Step by step solution

01

Step  1: Definition of specific heat 

The amount of heat that increase1 the degree of the temperature of a 1-mole substance is called specific heat.

02

 Finding the amount of mass

Th equation of heat is Q=m(ci∆Ti+Li+cw∆Tw)

95% heat has been increased in teh coffee same specific heat of the water and temperature difference Q=mc(cw∆Tc)mc(cw∆Tc)=m(ci∆Ti+Li+cw∆Tw)m=mc(cw∆Tc)m(ci∆Ti+Li+cw∆Tw)mc=ρWVc=0.3Kg

Applying all values

m=4200×0.3×302090×20+33400+4200×60)=0.0602Kg

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