Chapter 12: Problem 6
The half-life of the hydrogen isotope tritium is about 12 years. After a certain amount of time a fraction \(31 / 32\) of the atoms in the original sample has decayed. The time is most nearly equal to (A) 12 years (B) 24 years (C) 36 years (D) 48 years (E) 60 years
Short Answer
Expert verified
Answer: 60 years
Step by step solution
01
Write down the formula for exponential decay
The formula for exponential decay is:
\(N(t) = N_0 e^{-\lambda t}\),
where:
\(N(t)\): number of the substance left after time \(t\),
\(N_0\): initial amount of the substance,
\(\lambda\): decay constant,
\(t\): time elapsed.
02
Relate half-life to the decay constant \(\lambda\)
To relate the half-life \(T_{1/2}\) to the decay constant \(\lambda\), use the formula:
\(T_{1/2} = \frac{\ln{2}}{\lambda}\).
03
Find the decay constant \(\lambda\) for tritium
We are given that the half-life of tritium is 12 years. Using the formula from Step 2, we can find the decay constant \(\lambda\):
\(\lambda = \frac{\ln{2}}{T_{1/2}} = \frac{\ln{2}}{12}\).
04
Write down the fraction of tritium decayed and set up an equation
The fraction decayed is given to be \(31/32\). Therefore, the fraction remaining (not decayed) is \(1 - \frac{31}{32} = \frac{1}{32}\).
Now we can set up an equation for the remaining fraction of tritium:
\(\frac{N(t)}{N_0} = \frac{1}{32} = e^{-\lambda t}\).
05
Solve for time \(t\)
Substitute the value of \(\lambda\) found in Step 3 into the equation from Step 4:
\(\frac{1}{32} = e^{-\frac{\ln{2}}{12} t}\).
To solve for \(t\), we can take the natural logarithm of both sides:
\(\ln{\frac{1}{32}} = -\frac{\ln{2}}{12}t\).
Now, we can solve for \(t\):
\(t = \frac{12 \ln{(\frac{1}{32})}}{-\ln{2}} \approx 60\).
So, the time elapsed is most nearly equal to 60 years, which is option (E).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Half-Life Calculation
Understanding the concept of half-life is crucial in fields like nuclear physics, chemistry, and environmental science. A half-life is the time required for a quantity to reduce to half its initial value. In radioactive decay, it's the time it takes for half of the radioactive atoms in a sample to disintegrate.
To calculate the half-life when given a decay constant \(\lambda\), we use the formula: \[ T_{1/2} = \frac{\ln{2}}{\lambda} \]. Knowing the half-life helps us understand the longevity and decay rate of radioactive substances.
To calculate the half-life when given a decay constant \(\lambda\), we use the formula: \[ T_{1/2} = \frac{\ln{2}}{\lambda} \]. Knowing the half-life helps us understand the longevity and decay rate of radioactive substances.
Step-by-Step Approach to Half-Life Problems
Given the decay constant or the half-life, one can determine the remaining amount of a substance after any period using the right equations. It's a basic yet powerful tool in solving exponential decay problems.Tritium Decay
Tritium, or hydrogen-3, is a radioactive isotope with notable use in self-illuminating devices and as a tracer in environmental studies. Its decay is a great example to explore the principles of radioactivity. Tritium decays via beta emission, transforming into helium-3 with a relatively short half-life of about 12 years.
Due to its decay properties, tritium is an excellent candidate for half-life studies in physics and chemistry education.
Due to its decay properties, tritium is an excellent candidate for half-life studies in physics and chemistry education.
Decay Representation
The decay of tritium can be represented in equations that express the initial and remaining quantities of the isotope over time, helping us predict the amount present after a specific period.Radioactive Decay Equations
Radioactive decay is mathematically represented by equations that describe how unstable atoms lose energy by emitting radiation. The general formula for exponential decay of a radioactive substance is: \[ N(t) = N_0 e^{-\lambda t} \], where \(N(t)\) is the number of atoms remaining after time \(t\), \(N_0\) is the initial number of atoms, \(\lambda\) is the decay constant, and \(t\) is the elapsed time.
This equation is vital for understanding how radioactive substances change over time, and is a fundamental piece of knowledge for students studying nuclear physics.
This equation is vital for understanding how radioactive substances change over time, and is a fundamental piece of knowledge for students studying nuclear physics.
Application in Real-World Scenarios
By applying these equations, scientists and engineers can manage nuclear materials, date archaeological finds, and ensure safety in medical treatments involving radioactive isotopes.AP Physics Practice
Engaging with problems like the tritium decay example is perfect for AP Physics practice. These problems encompass a variety of concepts including exponential functions, logarithms, and of course, physics. They encourage critical thinking and a deep understanding of physical principles.
The practice of working through such exercises prepares students for the problem-solving nature of AP examinations.
The practice of working through such exercises prepares students for the problem-solving nature of AP examinations.