A simple pendulum is composed of a mass \(m\) attached to a massless string of length \(\ell\). The other end of the string is attached to the ceiling. A physical pendulum consists of a thin rod of uniform density with mass \(m\) and length \(\ell\). One end is attached to the ceiling by a frictionless bearing. Both the simple pendulum and the physical pendulum are displaced by an angle \(\theta\) from the vertical and released from rest. Which pendulum reaches the equilibrium \((\theta=0)\) position first? (A) The simple pendulum (B) The physical pendulum (C) They both reach the equilibrium position at the same time. (D) The answer depends on the mass of the pendulums. (E) None of the above

Short Answer

Expert verified
Answer: (B) The physical pendulum

Step by step solution

01

Formula for the period of a simple pendulum

The formula for the period of a simple pendulum is given by: \(T_s = 2\pi\sqrt{\frac{\ell}{g}}\), where \(T_s\) is the period of the simple pendulum, \(\ell\) is the length of the string, and \(g\) is the acceleration due to gravity.
02

Formula for the period of a physical pendulum

The formula for the period of a physical pendulum with a mass \(m\) and length \(\ell\) is given by: \(T_p = 2\pi\sqrt{\frac{(2/3)\ell}{g}}\), where \(T_p\) is the period of the physical pendulum.
03

Comparing the periods of the simple and physical pendulum

Comparing the expressions for the period of the simple pendulum and the physical pendulum, we see that the ratio of their periods is \(\frac{T_p}{T_s} = \frac{2\pi\sqrt{\frac{(2/3)\ell}{g}}}{2\pi\sqrt{\frac{\ell}{g}}} = \sqrt{\frac{2}{3}} < 1\). Since the ratio is less than 1, the period of the physical pendulum is shorter than the period of the simple pendulum.
04

Choosing the correct answer

We now know that the period of the physical pendulum is shorter than that of the simple pendulum. This means the physical pendulum will reach the equilibrium position first. Therefore, the correct answer is (B) The physical pendulum.

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