What is the effect of an obstacle (as opposed to an aperture) in the Fraunhofer diffraction limit?

Short Answer

Expert verified
Answer: In the Fraunhofer diffraction limit, the primary difference in the diffraction patterns produced by an obstacle and an aperture is that the pattern produced by the obstacle will generally be the inverse of the pattern produced by the aperture. The central bright spot observed in aperture diffraction will be replaced by a dark spot, known as the Poisson spot or the Arago spot, in the obstacle diffraction pattern.

Step by step solution

01

Understand Fraunhofer diffraction

Fraunhofer diffraction, also known as far-field diffraction, is a type of diffraction that occurs when the source, the aperture (or obstacle), and the screen are far away from each other, so that the path differences between the diffracted waves can be considered parallel. This condition simplifies the analysis of the diffraction pattern while still considering a wide range of physical situations.
02

Difference between obstacle and aperture

An aperture is an opening that allows light to pass through, while an obstacle is an object that blocks the light. In the context of Fraunhofer diffraction, we generally treat the aperture as the region through which light can pass, and the obstacle as the region blocking the light.
03

Set up the experiment

To study the effect of an obstacle in the Fraunhofer diffraction limit, we can consider a plane wave incident on a thin, opaque (non-transparent) obstacle of a specific shape. The transmitted wavefront will then be compared to the situation when the obstacle is replaced by an aperture of the same shape and size.
04

Compare the diffraction patterns

When the light encounters an aperture, it will be diffracted by the edges, generating a diffraction pattern on the screen. On the other hand, when the light encounters an obstacle, the light will be blocked by the obstacle, and the diffraction pattern will be formed due to the diffraction around the edges of the obstacle. The diffraction pattern caused by the obstacle will generally be the inverse of the pattern produced by the aperture, meaning that the bright regions will correspond to the dark regions in the aperture case, and the dark regions will correspond to the bright regions in the aperture case.
05

Effect of obstacle on Fraunhofer diffraction pattern

In the Fraunhofer diffraction limit, the effect of an obstacle can be summarized as follows: 1. The diffraction pattern produced by the obstacle will generally be the inverse of the pattern produced by the aperture. 2. The central bright spot observed in aperture diffraction will be replaced by a dark spot, known as the Poisson spot or the Arago spot, in the obstacle diffraction pattern. 3. The intensity distribution of the diffraction pattern will be influenced by the shape and size of the obstacle, and can be analyzed using the Babinet's principle, which states that the diffraction pattern of an obstacle is equal to the pattern of its complementary aperture, with the addition of a uniform background intensity filling the entire field of view. In conclusion, the effect of an obstacle in the Fraunhofer diffraction limit is to produce a diffraction pattern that is the inverse of the pattern produced by the corresponding aperture, with the central bright spot being replaced by a dark spot in the obstacle case. The intensity distribution is influenced by the shape and size of the obstacle and can be analyzed using Babinet's principle.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In the paraxial approximation, the Fresnel diffraction pattern of a slit may be specified uniquely by two normalized parameters: (1) the width of the slit measured as $$ \Delta u=\left[\frac{2}{\lambda}\left(\frac{1}{R_{s}}+\frac{1}{R_{0}}\right)\right]^{1 / 2} a $$ or alternatively the number \(n=(\Delta u)^{2} / 8\) of Fresnel linear zones unmasked, and (2) the angle of the observation point off the axis measured as \(\theta / \theta_{0}\) where \(\theta_{0}=\lambda / a\). Compare the diffraction patterns when \((a) a=1 \mathrm{~mm}, R_{s}=R_{0}=1 \mathrm{~m}\) and, \((b) a=2 \mathrm{~mm}, R_{\varepsilon}=R_{0}=4 \mathrm{~m}\).

A step function is a function whose value changes abruptly from zero to some constant. In general, this abrupt rise takes place over a small but finite interval of the argument. Also, the function may overshoot before converging to its final constant value. The rise-inlerval (or rise-time if the abscissa happens to be time) is usually defined as the increment in the argument over which the function changes from 10 to 90 percent of its final value. What is the rise-interval \(\delta u\) of the straight-edge intensity diffraction pattern? To what distance in the observation plane does this correspond for the special case of \(R_{\mathrm{s}}=R_{\mathrm{o}}=2 \mathrm{~m}\), \(\lambda=500 \mathrm{~nm}\) ? What is the percentage overshoot? Answer: \(\delta u=1.17, \delta x=1.17 \mathrm{~mm} ; 37\) percent.

You wish to construct a pinhole camera (no lens) with \(10 \mathrm{~cm}\) separation between pinhole and film plane. The film is sensitive to visible light \((\lambda \sim 500 \mathrm{~nm}) .\) What pinhole diameter would you choose for optimum resolution, i.e., smallest photographic image of a point object, and what order of magnitude of angular resolution would be obtained?

A zone plate is a screen made by blackening even-numbered (alternatively, oddnumbered) zones whose outer radii are given by \(\rho_{n}{ }^{2}=n \lambda R_{o}(n=1,2, \ldots) .\) Plane monochromatic waves incident on it are in effect focused on a point \(P_{o}\), distant \(R_{o}\) from the zone plate, since the wavefronts arriving at \(P_{0}\) from the odd-numbered zones are all in phase. Show that a sequence of such focus points exist. Show also that the zone plate focuses a point source at a distance \(p\) into a point image at a distance \(q\), where \(p\) and \(q\) are related by the familiar lens equation $$ \frac{1}{p}+\frac{1}{q}=\frac{1}{f}=\frac{\lambda}{\rho_{1}{ }^{2}} $$ Does an equation of this form hold for each of the other images?

Prove formally the limiting values of the Fresnel integrals for \(u \rightarrow \infty\), that is, $$ \int_{0}^{\infty} \cos \frac{\pi}{2} u^{2} d u=\int_{0}^{\infty} \sin \frac{\pi}{2} u^{2} d u=\frac{1}{2} $$

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free