What limitations must be put on the mathematical behavior of a transfer function at an infinite frequency if the Kramers-Kronig integrals are to converge? Answer: \(T_{r}(\infty)\) remains finite, \(T_{i}(\infty)=0\).

Short Answer

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Answer: The limitations are that \(T_{r}(\infty)\) remains finite (real part) and \(T_{i}(\infty)=0\) (imaginary part).

Step by step solution

01

Understand the Kramers-Kronig relations

Kramers-Kronig relations are a set of mathematical formulas that relate the real and imaginary parts of a complex function that describes the response of a physical system. They are used in various fields such as optics, acoustics, and electrical engineering. The Kramers-Kronig relations apply to functions that are analytic in the upper half-plane and have certain convergence properties.
02

Write the Kramers-Kronig relations for a transfer function

Let \(T(\omega)\) be the transfer function of a system. The real and imaginary parts of the transfer function can be written as \(T(\omega)=T_{r}(\omega)+iT_{i}(\omega)\). The Kramers-Kronig relations for the transfer function are given by: $$T_{r}(\omega)=\frac{1}{\pi}\text{P}\!\int_{-\infty}^{\infty}\frac{T_{i}(\omega')}{\omega'-\omega}\, d\omega'$$ $$T_{i}(\omega)=-\frac{1}{\pi}\text{P}\!\int_{-\infty}^{\infty}\frac{T_{r}(\omega')}{\omega'-\omega}\, d\omega'$$ where P denotes the Cauchy principal value integral.
03

Analyze the convergence properties

For the Kramers-Kronig integrals to converge, the integrand must satisfy certain conditions. According to the Kramers-Kronig relations, the transfer function must be analytic in the upper half-plane, and the real and imaginary parts should decay at infinity.
04

Determine the necessary conditions for convergence

In order for the Kramers-Kronig integrals to converge, the following conditions must be satisfied: 1. \(T_{r}(\omega)\) should remain finite as \(\omega \rightarrow \infty\). This ensures that the real part of the transfer function does not diverge at infinitely high frequencies. 2. \(T_{i}(\omega) \rightarrow 0\) as \(\omega \rightarrow \infty\). This ensures that the imaginary part of the transfer function decays at infinitely high frequencies, and the integral converges. These conditions ensure that the transfer function satisfies the required properties for the Kramers-Kronig relations to hold, and the integrals to converge. Therefore, the limitations on the mathematical behavior of a transfer function at an infinite frequency for the Kramers-Kronig integrals to converge are \(T_{r}(\infty)\) remains finite and \(T_{i}(\infty)=0\).

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Most popular questions from this chapter

Prove the similarity relation that if \(F(\omega)\) is the Fourier transform of \(f(t)\) then \((1 / a) F(\omega / a)\) is the Fourier transform of \(f(a t)\), where \(a\) is a real, positive constant.

A sinusoidal voltage \(V=V_{0} \cos \omega t\), whose frequency can be varied, is applied to the terminals of a network, and the component of the current in phase with \(V\) is found to be \(I_{r}=\left[V_{0} / R\left(1+\omega^{2} \tau^{2}\right)\right] \cos \omega t .\) Use (12.7.15) to find the out-of-phase component of current. What is the input impedance of the network?

Show that the Fraunhofer diffraction integral for a one-dimensional aperture, such as a single slit (Sec. 10.4) or a grating (Secs. \(10.7\) and 10.8) may be expressed in the form $$ \psi(s)=\breve{C} \int_{-\infty}^{\infty} \breve{T}(x) e^{i \theta x} d x $$ where \(s \equiv \kappa\left(\sin \theta_{o}+\sin \theta_{o}\right)\) and \(\breve{T}(x)\) is the aperture transmission function (9.4.19), possibly \(\dagger\) For further details concerning holography and other applications of Fourier analysis to optical problems, see M. Born and E. Wolf, "Principles of Optics," 3 ded., sec. \(8.10\), Pergamon Press, New York, 1965; A. Papoulis, "Systems and Transforms with Applications in Optics," McGraw-Hill Book Company, New York, 1968; and J. W. Goodman, "Introduction to Fourier Optics," McGraw-Hill Book Company, New York, \(1968 .\) complex, that expresses the wave- transmission properties of the aperture. Hence show that the diffracted-wave amplitude, except for a constant factor, is the Fourier transform of the aperture transmission function. It is thus no accident that the Fourier transform of a rectangular pulse (Prob. \(12.22\) ) is functionally the same as the Fraunhofer diffraction-amplitude function for a single slit, \(\sin u / u\).

Show that the Fourier transform of \(f(t)=e^{-(t / \tau)^{2}}\) is \(e^{-(\omega \tau / 2 \pi)^{2}}\). Show that the duration of \(f(t)\), defined by \((12.24)\), is \(\tau / 2\) and that the width \(\Delta \omega\) of its energy spectrum, defined by \((12.2 .5)\), is \(1 / \tau\) and hence that the product \(\Delta l \Delta \omega\) has precisely the minimum value \(\frac{1}{2}\) permitted by the uncertainty relation (12.2.7).

Show that when \(\psi(t)\) is expressed by (12.1.3), $$ \overline{|\psi(t)|^{2}}=\sum_{-\infty}^{\infty} \breve{A}_{n} \check{A}_{n}^{*}=\sum_{-\infty}^{\infty}\left|\check{A}_{n}\right|^{2} $$ where the bar denotes a time average taken over the fundamental period \(T_{1}\). This relation is very similar to (1.8.17), except for a factor of \(\frac{1}{2}\). Account for the difference.

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