The uncertainty relation (12.2.7) relates a waveform duration in the time domain to the bandwidth of its energy spectrum in the frequency domain. In the case of a traveling wave of finite duration, what can be said about the waveform extent \(\Delta x\) in the space domain and the spread \(\Delta \kappa\) of the wave numbers in the wave-number domain? In quantum mechanics the energy \(E\) and momentum \(p\) of a particle are related to frequency and wave number by de Broglie's relations \(E=\hbar \omega\) and \(p=\hbar \kappa\), where \(\hbar\) is Planck's constant divided by \(2 \pi\). On the basis of these relations and the uncertainty relation, obtain Heisenberg's uncertainty principle \(\Delta E \Delta t \geq \frac{1}{2} \hbar\) and \(\Delta p \Delta x \geq \frac{1}{2} \hbar\). This principle is an inescapable part of a wave description of nature.

Short Answer

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Question: Derive Heisenberg's uncertainty principle from the uncertainty relation in quantum mechanics and de Broglie's relations. Answer: Heisenberg's uncertainty principle states that the product of the uncertainties in energy and time, as well as the product of uncertainties in momentum and position, must be greater than or equal to a constant value, which is given by Planck's constant divided by 2. The derivation of this principle involves understanding the relations between waveform duration, bandwidth of the energy spectrum, space domain and wave-number domain, and considering de Broglie's relations between energy, momentum, frequency, and wave number. The final result of the derivation is: \(\Delta E \Delta t \geq \frac{1}{2} \hbar\) \(\Delta p \Delta x \geq \frac{1}{2} \hbar\)

Step by step solution

01

Understanding the Uncertainty Relation

The uncertainty relation states that the product of the uncertainty in time (\(\Delta t\)) and the uncertainty in frequency (\(\Delta \omega\)) is greater than or equal to \(\frac{1}{2 \pi}\). Mathematically, this can be written as: \(\Delta t \Delta \omega \geq \frac{1}{2 \pi}\)
02

Connecting Waveform Duration and Waveform Extent

In order to connect the waveform duration with the waveform extent, we need to consider the relation between wavelength (\(\lambda\)), wave number (\(\kappa\)) and the spatial extent (\(\Delta x\)). Since the wavelength equals the distance a wave repeats itself, and the wave number is the inverse of the wavelength, it can be written as: \(\kappa = \frac{1}{\lambda}\) By applying the uncertainty relation, we can find the relation between \(\Delta x\) and \(\Delta \kappa\): \(\Delta x \Delta \kappa \geq \frac{1}{2 \pi}\)
03

Implementing De Broglie's Relations

De Broglie's relations connect the energy \(E\) and momentum \(p\) to frequency \(\omega\) and wave number \(\kappa\): \(E = \hbar \omega\) \(p = \hbar \kappa\) Here, \(\hbar\) is Planck's constant divided by \(2 \pi\). We need to apply these relations to the uncertainties of energy and momentum, respectively. We have: \(\Delta E = \hbar \Delta \omega\) \(\Delta p = \hbar \Delta \kappa\)
04

Deriving Heisenberg's Uncertainty Principle

Now we can derive Heisenberg's uncertainty principle using the uncertainty relation found in Step 2 and de Broglie's relations found in Step 3. From the uncertainty relation for \(\Delta x \Delta \kappa\), we have: \(\Delta x \Delta \kappa \geq \frac{1}{2 \pi}\) Substitute \(p = \hbar \kappa\): \(\Delta x \Delta p \geq \frac{1}{2} \hbar\) Finally, applying the uncertainty relation between \(\Delta t\) and \(\Delta \omega\): \(\Delta t \Delta \omega \geq \frac{1}{2 \pi}\) Substitute \(E = \hbar \omega\): \(\Delta t \Delta E \geq \frac{1}{2} \hbar\) We have derived Heisenberg's uncertainty principle: \(\Delta E \Delta t \geq \frac{1}{2} \hbar\) \(\Delta p \Delta x \geq \frac{1}{2} \hbar\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Uncertainty Relation
The uncertainty relation is a fundamental concept in quantum physics, articulating the limits of measuring certain pairs of properties simultaneously. It posits that the more accurately you measure one property (like position), the less accurately you can measure its complementary property (like momentum). This is not a limitation of our instruments' precision, but rather a fundamental characteristic of the quantum realm.

For instance, in the context of waves, there's a similar uncertainty relation between a wave's time duration and its frequency bandwidth. The product of the uncertainty in time measurement \( \Delta t \) and the uncertainty in frequency \( \Delta \omega \) is always greater than or equal to a constant \( \frac{1}{2\pi} \), indicating an inverse relationship: as one measurement becomes more precise, the other becomes less so. This core idea is what leads to the understanding of Heisenberg's uncertainty principle in quantum mechanics.
Wave-Particle Duality
Wave-particle duality is a central idea of quantum mechanics that addresses the nature of light and matter at the microscopic scale. It suggests that elementary particles, such as electrons and photons, exhibit both wave-like and particle-like properties. An electron, for example, can display interference patterns, which are characteristic of waves, in experiments such as the double-slit experiment. Yet, it also exhibits particle characteristics, evidenced when it impacts a screen, presenting as a point of interaction.

The concept of wave-particle duality is best exemplified by de Broglie's hypothesis, which states that all matter has a wave-like nature and can be described by a wavelength \( \lambda \). This leads to another profound implication: we cannot fully describe quantum objects using classical terms like 'particle' or 'wave'—they are fundamentally quantum entities that transcend classical physics' strict categorizations.
De Broglie's Relations
De Broglie's relations play a significant role in the bridge between quantum physics and classical physics. They form a link by relating the wave-like behavior of particles to their momentum and energy—fundamental attributes of particles as understood in classical mechanics.

According to these relations, the energy \( E \) of a particle is directly proportional to its frequency \( \omega \) by the relation \( E = \hbar \omega \) where \( \hbar \) is the reduced Planck's constant. Similarly, the momentum \( p \) is related to the wave number \( \kappa \) through the expression \( p = \hbar \kappa \). These equations underscore the dual nature of quantum entities, connecting the wave aspect \( \omega, \kappa \) to classical properties \( E, p \) of particles, and they are the very cornerstone that enables the derivation of Heisenberg's uncertainty principle, a cornerstone in the quantum mechanics field.

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Most popular questions from this chapter

The voltage gain of a multistage low-pass a mplifier is accurately approximated by the gaussian function $$ |\breve{G}(\omega)|=G_{0} e^{-(\omega / 2 \pi \Delta \omega)^{2}} . $$ Show that \(\Delta \omega\) is the rms bandwidth of the amplifier. Show also that the so-called \(u p p e r\) halfpower frequency \(\nu_{0}\) [the frequency at which \(\left(|\breve{G}| / G_{0}\right)^{2}=\frac{1}{2}\) ] is related to \(\Delta \omega\) by $$ \nu_{0} \approx 0.6 \Delta \omega, $$ where \(\nu_{0}\) is an ordinary (cyclic) frequency. Show then that the uncertainty relation (12.2.7) implies that $$ \nu_{0} \Delta t \approx \frac{1}{3} $$ when \(\Delta t\), the duration of a narrow pulse whose frequency spectrum is limited by the amplifier, has its minimum permitted value. This form of the uncertainty relation expresses reasonably well the relation between the rise- time of an amplifier (see Prob. 11.4.3 for a definition of risetime) and its bandwidth expressed by its upper half-power frequency.

What limitations must be put on the mathematical behavior of a transfer function at an infinite frequency if the Kramers-Kronig integrals are to converge? Answer: \(T_{r}(\infty)\) remains finite, \(T_{i}(\infty)=0\).

A sinusoidal voltage \(V=V_{0} \cos \omega t\), whose frequency can be varied, is applied to the terminals of a network, and the component of the current in phase with \(V\) is found to be \(I_{r}=\left[V_{0} / R\left(1+\omega^{2} \tau^{2}\right)\right] \cos \omega t .\) Use (12.7.15) to find the out-of-phase component of current. What is the input impedance of the network?

Establish the integral $$ \int_{0}^{\infty} \sin a t \cos b t d t=\frac{a^{2}}{a^{2}-b^{2}} $$ by first multiplying the integrand by \(e^{-s t}\) and allowing \(s \rightarrow 0\) after integration. This, or a similar artifice, is of necessary in evaluating Fourier transform integrals. A Fourier transform so evaluated is then described as a limiting form.

Show that the amplitude spectrum of a rectangular pulse of the sinusoidal oscillation \(e^{-i \omega_{0} t}\) lasting from \(-\tau\) to \(+\tau\) is given by $$ F(\omega)=2 a \frac{\sin \left(\omega-\omega_{0}\right) \tau}{\left(\omega-\omega_{0}\right) \tau} $$ Relate this spectrum to that of the rectangular pulse discussed in Sec. 12.2. Generalize this result into a modulation theorem: if \(F(\omega)\) is the transiorm of \(f(t)\), then \(F\left(\omega-\omega_{0}\right)\) is the transform of \(f(t) e^{-i \omega_{0} t}\). What form does the theorem take if \(e^{-i \omega_{0} t}\) is replaced by \(\cos \omega_{0} t\) ?

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