Chapter 5: Problem 3
Each possible normal mode of oscillation of a distributed system constitutes a mechanical degree of freedom of the system. According to the classical equipartition-of-energy theorem, each oscillatory degree of freedom is to be assigned an average thermal energy of \(k T\), where \(k\) is Boltzmann's constant and \(T\) is the absolute temperature. Hence the internal thermal energy per unit volume of a monatomic gas should be \(E_{v}=n k T\), with \(n\) given by (5.7.11). For a mole of monatomic gas, kinetic theory tells us that the internal energy is \(E_{\mu}=\frac{3}{2} R T\), where \(R\) is the gas constant per mole. We can bring the two viewpoints into agreement by choosing a suitable value of \(\omega_{\max }\). Compute this value and show that the minimum wavelength is of the order of the mean spacing of the atoms in the gas.
Short Answer
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Key Concepts
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