The fluid in the vicinity of an arbitrary point \(P\) is rotating with the
angular velocity \(\omega\) with respect to an inertial frame. Take an origin
for a position vector \(\mathbf{r}\) at \(P\) and show that the velocity
\(\mathbf{u}\) with respect to \(P\) of fluid in the vicinity of \(P\), whose
position vector is \(\mathbf{r}\), is given by \(\mathbf{u}=\omega \mathbf{X}
\mathbf{r}\). If \(\mathbf{v}_{\boldsymbol{P}}\) is the velocity of transport of
the point \(P\) (with respect to an incrtial frame), then the velocity of the
fluid in the vicinity of \(P\) with respect to the inertial frame is
\(\mathbf{v}=\mathbf{v}_{P}+\omega \times \mathbf{r} .\) Show that
\(\omega=\frac{1}{2} \mathbf{v} \times \mathbf{v}\) by taking the curl of
\(\mathbf{v}\).