Define the mean pressure in a stressed elastic medium to be \(P=-\frac{1}{3}\left(f_{x x}+f_{x v}+f_{x t}\right)\), an invariant of the stress dyadic. Show that any stress dyadic \(\boldsymbol{F}\) can then be written as the sum of a pure shear dyadic and a dyadic representing mean pressure.

Short Answer

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Answer: A stress dyadic can be decomposed into a pure shear dyadic and a dyadic representing mean pressure by using the equation \(\boldsymbol{F}=\boldsymbol{S}+\boldsymbol{P}\), where \(\boldsymbol{F}\) is the stress dyadic, \(\boldsymbol{S}\) is the pure shear dyadic, and \(\boldsymbol{P}\) is the dyadic representing mean pressure.

Step by step solution

01

Defining Mean Pressure and Pure Shear Components

The stress dyadic \(\boldsymbol{F}\) can be represented as a 3x3 matrix, with components \(f_{ij}\). The mean pressure \(P\) is given as: \(P=-\frac{1}{3}\left(f_{x x}+f_{x v}+f_{x t}\right)\) Now, we need to define the dyadic representing mean pressure, let's call it \(\boldsymbol{P}\). Since the mean pressure is a scalar, we multiply it by the identity matrix \(\boldsymbol{I}\) to create a dyadic: \(\boldsymbol{P}=P\boldsymbol{I}\) The pure shear dyadic \(\boldsymbol{S}\) can be defined as the difference between the stress dyadic \(\boldsymbol{F}\) and the dyadic representing mean pressure \(\boldsymbol{P}\). Mathematically, the pure shear dyadic is given as: \(\boldsymbol{S}=\boldsymbol{F}-\boldsymbol{P}\) Our aim is to show that the stress dyadic can be expressed as a sum of the pure shear dyadic and the dyadic representing mean pressure, so, that: \(\boldsymbol{F}=\boldsymbol{S}+\boldsymbol{P}\)
02

Proving the Decomposition of the Stress Dyadic

We have defined our pure shear dyadic as being: \(\boldsymbol{S}=\boldsymbol{F}-\boldsymbol{P}\) By adding \(\boldsymbol{P}\) to both sides of the equation, we get: \(\boldsymbol{S}+\boldsymbol{P}=\boldsymbol{F}\) Thus, we have shown that the stress dyadic \(\boldsymbol{F}\) can be written as the sum of a pure shear dyadic \(\boldsymbol{S}\) and a dyadic representing mean pressure \(\boldsymbol{P}\). Finally, we can say that any stress dyadic \(\boldsymbol{F}\) can be decomposed into a pure shear dyadic and a dyadic representing mean pressure as given by the equation \(\boldsymbol{F}=\boldsymbol{S}+\boldsymbol{P}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Pressure in Elastic Medium
The concept of mean pressure is a fundamental aspect of understanding how forces are distributed in an elastic medium. In the context of solid mechanics, when a material is subjected to stresses from various directions, it experiences pressure, which is essentially the average of those stresses.

According to the given exercise, the mean pressure, denoted by the symbol 'P', is calculated using the formula: \(P = -\frac{1}{3}(f_{xx}+f_{xy}+f_{xz})\). This formula considers the normal stresses acting on the medium on the x, y, and z directions. The negative sign indicates that compression is considered as negative pressure according to sign convention in solid mechanics.

It's important to recognize that mean pressure is an invariant of the stress dyadic. In this context, an invariant means that its value does not change regardless of the orientation of the material or the coordinate system employed. This property is significant for analyzing materials under stress, as it allows for a simpler and more universal way of characterizing the state of stress at a point, independent of the specific orientation of the stressors.

By understanding the concept of mean pressure, students can gain better insights into the distribution of forces within a material and how the material may behave or deform when subjected to external stresses.
Pure Shear Dyadic
In mechanics, the term 'pure shear' refers to a state of stress where the deformation of the material does not involve any change in volume. The pure shear dyadic, within the context of the exercise, distinguishes the distortion component of stress that alters the material's shape without changing its volume.

This particular component of stress is mathematically captured by the pure shear dyadic, denoted as \(\boldsymbol{S}\), which represents the shear stresses in a material while excluding the effects of mean pressure. To construct this dyadic, the influence of mean pressure is removed from the total stress dyadic, leaving only the shear components.

The formula for the pure shear dyadic is given by: \(\boldsymbol{S} = \boldsymbol{F} - \boldsymbol{P}\), where \(\boldsymbol{F}\) is the original stress dyadic and \(\boldsymbol{P}\) represents the dyadic of mean pressure. By subtracting the mean pressure dyadic from the original stress dyadic, we isolate the pure shear part that strictly pertains to the distortion of the elastic medium, which is vital for understanding how materials respond to stress without volumetric changes.
Invariant of Stress Dyadic
The invariant of a stress dyadic is a term used in solid mechanics to denote quantities associated with a stress state that remain unchanged under a transformation of coordinates. This means that these invariants are the same for every observer, irrespective of how they are looking at the stressed object or the coordinate system they are using.

For the stress dyadic \(\boldsymbol{F}\), there are several invariants that are typically considered, the most fundamental of which is the mean pressure 'P'. This invariant is particularly significant as it allows engineers and scientists to describe the stress state in a manner that is not dependent on the orientation of the body or the coordinate system applied – a crucial feature for analyzing and predicting the behavior of materials under load.

Understanding the invariant nature of mean pressure helps in simplifying complex stress analysis problems. By being able to decompose the stress dyadic into a pure shear component and a component representing mean pressure, it becomes possible to focus on the deformation characteristics of materials, as opposed to just their strength characteristics. This insight is especially helpful for designers and engineers when considering how objects will deform when exposed to various force fields. Such an understanding is a key step towards designing safer and more reliable structures and components.

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Most popular questions from this chapter

Show that the nine directional cosines \(\gamma_{i j}\) cannot be considered the components of a (physical) dyadic by examining their transformation properties. Show that two successive rotations \(\gamma_{i j}, \gamma_{i j}^{\prime}\) are in fact equivalent to the single rotation \(\gamma_{i j}^{\prime \prime}\), whose components are found by the matrix multiplication of \(\gamma_{i j}\) and \(\gamma_{i j}^{\prime}\)

Show (a) that there are a maximum of 21 independent elastic constants, using the fact that both stress and strain are symmetric dyadics, and \((b)\) that there exists a symmetry among the constants arising from the reciprocity relations $$ \frac{\partial f_{i j}}{\partial e_{k !}}=\frac{\partial f_{k}}{\partial \epsilon_{i j}} $$ where \(i j\) and \(k l\) stand for pairs of values of \(x, y, z\).

Discuss the energy content of sinusoidal plane waves traveling in the positive \(x\) direction in a solid isotropic elastic medium. Treat separately irrotational waves and solenoidal waves.

An elastic medium suffers a simple shear in the \(y\) direction such that a point originally at \((x, y)\) moves to the position \((x, y+\gamma x)\), where \(\gamma=\partial_{\eta} / \partial x \ll 1\) is the shearing strain. Examine the transformation of the circle \(x^{2}+y^{2}=a^{2}\) into an ellipse to find the magnitudes and orientation of the principal axes due to a simple shear. \(A\) nswer: To a first order in \(x\) the angles between the principal axes and the \(x\) axis are \((\pi+\gamma) / 4,(3 \pi+\gamma) / 4 ;\) their magnitudes are \(a\left[1 \pm\left(\gamma / 2+\gamma^{2} / 8+\cdots \cdot\right)\right]\).

Let \(\mathbf{n}_{\mathrm{t}}\) be a unit vector of variable direction with an origin at the coordinate origin. Let the position vector \(\mathbf{r}\) from the origin be determined by the equation where \(\mathbf{S}\) is a symmetric dyadic. When \(\mathbf{n}_{1}\) varies in direction, its terminus describes a unit sphere. Show that the terminus of \(\mathbf{r}\) then describes an ellipsoid. Hint: Assume the coordinate system is oriented such that \(\mathbf{S}\) is diagonal.

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