Show that $$ \begin{aligned} &\mathbf{E}=(1+j j) E_{1} e^{j(\omega t-\alpha o)} \\ &\mathbf{B}=(-1 j+j) \frac{E_{1}}{c} e^{j(\omega t-\alpha t)} \end{aligned} $$ represent a circularly polarised plane wave. (Note that \(j=\sqrt{-1}\), while \(\mathbf{1}, \mathbf{j}\) are the cartesian unit vectors in the \(x\) and \(y\) directions!) If you watch the time variation of the electric field at a fixed position, will the direction of the field rotate in the right-or left-handed sense with respect to the direction of travel \((+z) ?\) If you could take a snapshot of the electric field over space, in which sense would the direction rotate? Repeat these questions for the magnetic field. How would you represent a circularly polarized wave of the opposite handedness? Answer: Left-handed; right-handed; magnetic same as electric; reverse sign of \(j\) in coefficients.

Short Answer

Expert verified
How can we represent a wave of the opposite handedness? Answer: The given electric and magnetic fields represent a circularly polarized plane wave with left-handed rotation for the electric field and right-handed rotation for the magnetic field. To represent a wave of the opposite handedness, we can change the sign of \(j\) in the coefficients, as shown in the fields \(\mathbf{E'}\) and \(\mathbf{B'}\).

Step by step solution

01

Check constants of amplitudes

Let's first analyze the amplitude of the electric field \(\mathbf{E}\) and the magnetic field \(\mathbf{B}\): $$ \mathbf{E} = (1 + jj) E_1 e^{j(\omega t - \alpha z)} \\ \mathbf{B} = (-j + j) \frac{E_1}{c} e^{j(\omega t - \alpha z)} $$ Both the electric field \(\mathbf{E}\) and the magnetic field \(\mathbf{B}\) have amplitude constants of \(E_1\) and \(E_1/c\) respectively. This satisfies the first required property of a circularly polarized wave.
02

Check phase difference

The phase of the electric field is \(\omega t - \alpha z\) and that of the magnetic field is also \(\omega t - \alpha z\). Therefore, the phase difference between the electric and magnetic fields is: $$ \Delta \phi = (\omega t - \alpha z) - (\omega t - \alpha z) = 0 $$ Since the given phase difference \(\Delta \phi = 0\) which is equal to \(n\pi\) (for n=0 in this case), then this is either linearly polarized or circularly polarized. We need to check the handedness to be sure.
03

Determine handedness of electric field

The sign of \(j\) in the coefficients determines the handedness of the wave. Looking at the electric field: $$ \mathbf{E} = (1 + jj) E_1 e^{j(\omega t - \alpha z)} $$ The coefficient of the \(y\)-component is positive, which means that as the electric field increases in the \(x\)-direction, it also increases in the \(y\)-direction. This would cause a counterclockwise rotation in the \(xy\)-plane, which is left-handed with respect to the \(+z\) direction of travel.
04

Determine handedness of magnetic field

Now we need to check the magnetic field: $$ \mathbf{B} = (-j + j) \frac{E_1}{c} e^{j(\omega t - \alpha z)} $$ The coefficient of the \(x\)-component is negative and the coefficient of the \(y\)-component is positive. This would cause a clockwise rotation in the \(xy\)-plane, which is right-handed with respect to the \(+z\) direction of travel.
05

Represent wave of opposite handedness

To represent a circularly polarized wave of the opposite handedness, we simply need to reverse the sign of \(j\) in the coefficients of the electric and magnetic fields. The new fields would be: $$ \mathbf{E'} = (1 - jj) E_1 e^{j(\omega t - \alpha z)} \\ \mathbf{B'} = (j + j) \frac{E_1}{c} e^{j(\omega t - \alpha z)} $$ In conclusion, the given electric and magnetic fields represent a circularly polarized wave with left-handed rotation for the electric field and right-handed rotation for the magnetic field. A wave of the opposite handedness can be represented by changing the sign of \(j\) in the coefficients.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polarization of Waves
Polarization is a fundamental characteristic of waves that describes the orientation of their oscillations. For electromagnetic waves, including light, this refers to the direction of the electric field's oscillation. There are several types of polarization, such as linear, circular, and elliptical. In linear polarization, the electric field oscillates in a single plane. However, for circular polarization, the electric field rotates in a circular manner as the wave propagates. This creates a helical pattern in the space through which the wave travels.

The key indicator of circular polarization is a constant phase difference between the two perpendicular components of the electric (or magnetic) field. For instance, in a right-handed circularly polarized wave, if you were to look along the direction of wave travel, the electric field vector would rotate clockwise. Conversely, it would rotate counterclockwise for a left-handed wave. Understanding these rotations and the polarization concept are crucial, not just for comprehending the fundamental properties of light, but also for applications such as optical filters and communication systems.
Properties of Electromagnetic Waves
Electromagnetic waves are fascinating phenomena that encompass a wide range of frequencies, from radio waves to gamma radiation. These waves are characterized by their wavelength, frequency, speed, amplitude, and polarization. They travel at the speed of light in a vacuum (\( c \text{, which is approximately } 3 \times 10^8 \text{ meters per second}\)).

Their transverse nature means that the oscillations of the electric and magnetic fields are perpendicular to the direction of wave travel, as well as to each other. For a wave to be considered circularly polarized, its electric and magnetic field components should rotate with constant amplitude and maintain a consistent phase relationship. This is demonstrated in the textbook exercise, where the electric and magnetic fields of a circularly polarized wave are modeled with their corresponding mathematical representations.
Phase Difference in Waves
The concept of phase difference plays a crucial role in the characterization of waves. Phase difference is the offset in the oscillation cycles of two waves or two components of a wave. It is typically measured in radians or degrees. When two components of a wave, such as the x and y components of an electromagnetic wave's electric field, have a phase difference of \( \pm \frac{\pi}{2} \) (or \( \pm 90^\circ \) for degrees), the wave is said to be circularly polarized.

In the provided exercise, the phase difference between the electric and magnetic fields is zero, implying a special condition where the fields could either be linearly polarized or part of a circularly polarized wave depending on their individual orientations and rotation. The significance of phase difference in engineering and physics cannot be understated, as it's critical in the synthesis and analysis of wave behavior in a multitude of applications.
Handedness of Polarization
Handedness, or chirality, in polarization refers to the direction in which the electric (or magnetic) field rotates as the wave propagates. The two types of handedness are right-handed and left-handed circular polarization. To determine the handedness of a wave, one can envision looking down along the wave's direction of travel. If the electric field rotates clockwise, the polarization is right-handed; if it rotates counterclockwise, the wave is left-handed.

This concept is particularly important when discussing the interaction of polarized light with materials, as certain substances can distinguish between left and right-handed polarization, a property employed in the fields of chemistry and biology to investigate molecular structures. As demonstrated in the exercise solution, the handedness can be manipulated by adjusting the phase and amplitude of the wave components, allowing for the creation of waves with the desired characteristics.

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Most popular questions from this chapter

From \((8.7 .18)\) show that the phase velocity of the wave in a waveguide is $$ c_{p}=\frac{\omega}{\kappa_{x}}=\frac{c}{\left[1-\left(\lambda_{4} / \lambda_{e}\right)^{2}\right]^{1 / 2}} $$ Note that this exceeds the velocity of light \(c !\) Find the group velocity \(c_{\theta}=d \omega / d k_{x}\) and show that $$ c_{p} c_{g}=c^{2} $$ Explain the distinction between \(c_{\rho}, c_{,}\)and \(c_{p}\) in terms of the plane-uave analysis of Prob. \(8.7 .6\) for the \(\mathrm{TE}_{10}\) mode in rectangular waveguide.

A waveguide becomes a resonant cavity upon placing conducting walls at the two ends. Show that a resonance occurs when the length \(L\) is an integral number \(n\) of guide halfwavelengths \(\lambda_{e} / 2 ;\) specifically, \(\left(\frac{\omega}{c}\right)^{2}=\left(\frac{l \pi}{a}\right)^{2}+\left(\frac{m \pi}{b}\right)^{2}+\left(\frac{n \pi}{L}\right)^{2} \quad\) rectangular parallelepiped \(\left(\frac{\omega}{c}\right)^{2}=\left(\frac{u_{l m}}{a}\right)^{2}+\left(\frac{n \pi}{L}\right)^{2} \quad\) right circular cylinder. Cavity modes, requiring three integral indices, are named \(\mathrm{TE}_{l m n}\) or \(\mathrm{TM}_{l m n} . \mathrm{Make}\) a mode chart for cylindrical cavities by plotting loci of resonances on a graph of \((d / L)^{2}\) against \((f d)^{2}\), where \(d \equiv 2 a, f \equiv \omega / 2 \pi . \dagger\)

A charged particle in an electromagnetic field experiences the Lorentz force $$ \mathbf{F}=q(\mathbf{E}+\mathbf{v} \times \mathbf{B}), $$ where \(q\) is the charge and \(\mathbf{v}\) the (vector) velocity of the particle. Show that an electromagnetic wave in free space acts on a charged particle primarily through its electric field, the magnetic interaction being smaller by at least the ratio \(|\mathbf{v}| / c\).

Consider an E-field line of force, i.e., a continuous line everywhere parallel to the local direction of \(\mathbf{E}\), deflected at the boundary between two uniform media. Show that the exit line of force lies in the plane determined by the entrance line and the normal to the boundary surface and that the angles of incidence \(\theta_{1}\) and exit \(\theta_{2}\), measured with respect to the normal, are related by the Snell's law equation $$ \frac{1}{\kappa_{\theta 1}} \tan \theta_{1}=\frac{1}{K_{\theta 2}} \tan \theta_{2} \text {. } $$ What are the corresponding equations for \(\mathbf{B}, \mathbf{D}\), and \(\mathbf{H}\) ?

(a) Use Ampère's law (8.6.4) to prove that the current density \(J(z)\) in the conductor of Fig. \(8.6 .2\) is related to the net magnetic field just outside the conductor by $$ B_{\text {outeide }}=\mu_{0} \int_{0}^{\infty} J(z) d z=\mu_{0} K, $$ where the integral symbolized by \(K\) has the dimensions of a surface current density, namely, amperes per meter. \((b)\) Consider an artificial model whereby the surface current \(K\) is distributed uniformly in the skin layer \(0

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