Show that the right-hand side of \((84.16)\) can be written in the form $$ \int_{V} \nabla \cdot \mathbf{T} d v $$ where \(\mathrm{T}\) is the Maxwell stress tensor $$ \mathbf{T}={ }_{0} \mathbf{E} \mathbf{E} \mathbf{E}+\frac{\mathbf{1}}{\mu_{0}} \mathbf{B B}-\mathbf{1}\left(\frac{1}{2} \epsilon_{0} E^{2}+\frac{B^{2}}{2 \mu_{0}}\right) $$ Then apply Gauss' theorem to convert the integral to the surface-integral form $$ \int_{S} \mathbf{T} \cdot d \mathbf{S} . $$

Short Answer

Expert verified
Question: Show that the right-hand side of equation (84.16) can be written in the form of a volume integral with the Maxwell stress tensor, and then apply Gauss' theorem to convert the volume integral into a surface integral. Answer: We first introduced the Maxwell stress tensor and showed that the right-hand side of equation (84.16) can be written as a volume integral involving the Maxwell stress tensor. Then, by applying Gauss' theorem, we were able to convert this volume integral to a surface integral.

Step by step solution

01

Introduce the Maxwell Stress Tensor

The Maxwell stress tensor \(\mathbf{T}\) is given by: $$ \mathbf{T}={}_0 \mathbf{E} \mathbf{E} \mathbf{E}+\frac{\mathbf{1}}{\mu_{0}}\mathbf{B B}-\mathbf{1}\left(\frac{1}{2} \epsilon_{0} E^{2}+\frac{B^{2}}{2\mu_{0}}\right) $$ where \(\mathbf{E}\) is the electric field vector, \(\mathbf{B}\) is the magnetic field vector, \(\epsilon_0\) is the vacuum electric permittivity, and \(\mu_0\) is the vacuum magnetic permeability.
02

Write the Right-hand Side of \((84.16)\) as a Volume Integral

We want to show that the expression in the right-hand side of \((84.16)\) can be written as: $$ \int_{V} \nabla \cdot \mathbf{T} d v $$ To achieve this, we can write \(\nabla \cdot \mathbf{T}\) in terms of its components, then show that it matches the components of the right-hand side of \((84.16)\).
03

Apply Gauss' Theorem

Gauss' theorem states that the volume integral of the divergence of a vector field over a volume V is equal to the surface integral of the vector field over the boundary surface S of volume V. Mathematically, it can be expressed as: $$ \int_{V} \nabla \cdot \mathbf{T} d v = \int_{S} \mathbf{T} \cdot d \mathbf{S} $$ Applying Gauss' theorem, we can convert the volume integral obtained in Step 2 to a surface integral: $$ \int_{S} \mathbf{T} \cdot d \mathbf{S} $$ Conclusion: We have shown that the right-hand side of \((84.16)\) can be written in the form of a volume integral involving the Maxwell stress tensor, as well as converted this expression to a surface integral using Gauss' theorem.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gauss' theorem
Understanding Gauss' theorem, also known as Gauss' divergence theorem, is foundational for solving various problems in vector calculus and electromagnetism.

Gauss' theorem connects the flow of a vector field through a closed surface to the behavior of the vector field inside the volume. In more intuitive terms, it tells us that the 'net outflow' of a vector field through a surface is equal to the 'source strength' within the surface. Mathematically, it states that the volume integral of the divergence of a vector field over a volume, V, is equivalent to the surface integral of that vector field through the boundary surface, S. This can be written as:\[\int_{V} abla \cdot \mathbf{F} \, dV = \int_{S} \mathbf{F} \cdot d\mathbf{S}\] where \(\mathbf{F}\) is a vector field. In our exercise, we see this principle applied to the Maxwell stress tensor, allowing us to express complex electromagnetic interactions with simpler surface integrals.
Electric Field
The electric field, denoted by \(\mathbf{E}\), describes the electric force experienced by a stationary point charge at any location in space. It is a vector field, which means it has both magnitude and direction.

Electric fields are created by electric charges, or by changing magnetic fields, and they exert forces on other electric charges within the field. The strength of the electric field at a point in space is directly proportional to the force experienced by a unit positive charge placed at that point. In equations, the Maxwell stress tensor incorporates the electric field to calculate the force per unit area on a hypothetical surface within the field, making it a powerful tool in analyzing electromechanical stress.
Magnetic Field
The magnetic field, represented by \(\mathbf{B}\), is the magnetic force per unit charge and velocity that a moving charge would experience in a given location. Similar to the electric field, the magnetic field is also a vector field.

Magnetic fields arise from moving electric charges (currents) and are fundamental to the operation of electrical devices and the existence of magnetic materials. They play a crucial role in Maxwell's equations, which describe the fundamentals of electromagnetism. In the context of this exercise, the magnetic field interacts with the electric field within the Maxwell stress tensor to determine the electromagnetic force distribution.
Volume Integral
A volume integral represents the total quantity of some scalar valued function throughout a three-dimensional region. It is a type of multiple integral where integration is extended over a three-dimensional volume.

In electromagnetism, volume integrals are used to calculate properties that are distributed throughout a space, such as charge, mass, or energy density. When you perform a volume integral of a vector field's divergence, like when applying the Maxwell stress tensor, you're essentially summing up the 'source' or 'sink' contributions of that vector field throughout the volume of interest.The Maxwell stress tensor involves the volume integral, which ultimately transforms to a surface integral. This step simplifies the calculations and is a practical application of Gauss' theorem.
Surface Integral
A surface integral can be thought of as the two-dimensional analog of a line integral, extended over a surface. It deals with integrating a scalar function or the normal component of a vector field over a surface.

Surface integrals are a critical tool in physics and engineering, especially when calculating flux across a surface. In the context of the Maxwell stress tensor and electromagnetism, performing a surface integral of the stress tensor over a closed surface gives you a measure of the total force acting on that surface due to the electric and magnetic fields. This force calculation is essential for understanding and designing systems that contain or generate electromagnetic fields.

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Most popular questions from this chapter

The text following (8.2.10) refers to low-frequency (or dc) laboratory measurements of \(\epsilon_{0}\) and \(\mu_{0}\). How could you determine these constants? What logical chain of definitions and calibrations would be needed?

Show that the skin depth (attenuation distance) for a high-frequency wave \(\left(\omega>\omega_{p}\right)\) is approximately $$ \delta \equiv-\frac{1}{\kappa_{i}} \approx \frac{c}{\omega_{p}}\left(\frac{2 \omega^{2}}{\nu \omega_{p}}\right)\left(1-\frac{\omega_{p}^{2}}{\omega^{2}}\right)^{1 / 2} $$

(a) From \((8.7 .10)\) and \((8.7 .13)\), show that the guided ave impedance \(\left(E_{x}{ }^{2}+E_{y}{ }^{2}\right)^{1 / 2} /\) \(\left(H_{x}{ }^{2}+H_{z}{ }^{2}\right)^{1 / 2}\) is \(Z_{\mathrm{TE}}=\frac{Z_{0}}{\left[1-\left(\lambda_{0} / \lambda_{e}\right)^{2}\right]^{1 / 2}} \quad\) TE modes \(Z_{\text {T? }}=Z_{0}\left[1-\left(\lambda_{0} / \lambda_{c}\right)^{2}\right]^{1 / 2} \quad\) TM modes, where \(Z_{0}\) is the unbounded wave impedance \((8.3 .10)\) or, more generally, \((8.3 .12) .(b)\) For the TE o dominant mode in rectangular waveguide, show that the peak potential difference between opposite points in the cross section is $$ V_{0}=\left[\int_{0}^{b} E_{y}\left(x=\frac{1}{2} a\right) d y\right]_{p e s k}=b E_{0} $$ and that the peak axial current flowing in the top wall is $$ I_{0} \equiv\left[\frac{1}{\mu_{0}} \int_{0}^{a} B_{x}(y=b) d x\right]_{\text {pak }}=\frac{2 a E_{0}}{\pi Z_{\mathrm{TE}}} $$ Since the result of Prob. 8.7.10b can be written $$ \bar{P}=\frac{a b}{4} \frac{E_{0}{ }^{2}}{Z_{\mathrm{TB}}} $$ we can define three other (mode-dependent) waveguide impedances as follows: $$ \begin{aligned} &Z_{V, I}=\frac{V_{0}}{I_{0}}=\frac{\pi}{2}\left(\frac{b}{a} Z_{\mathrm{TE}}\right) \\ &Z_{P, V}=\frac{V_{0}{ }^{2}}{2 P}=2\left(\frac{b}{a} Z_{\mathrm{TE}}\right) \\\ &Z_{P, I}=\frac{2 \bar{P}}{I_{0}{ }^{2}}=\frac{\pi^{2}}{8}\left(\frac{b}{a} Z_{\mathrm{TE}}\right) \end{aligned} $$ which differ by small numerical factors. Only systems supporting a TEM mode (e.g., Sec. 8.1), have a unique impedance.

Consider a general tu o-conductor transmission line for which the conductors have a (round-trip) series resistance per unit length \(R_{1}\) and the medium between conductors has a leakage conductance per unit length \(G_{1}\). Show that the valtage and current waves then obey the telegrapher's equalion $$ \frac{\partial^{s} v}{\partial s^{2}}=L_{1} C_{3} \frac{\partial^{s} v}{\partial r^{2}}+\left(R_{1} C_{1}+G_{1} L_{1}\right) \frac{\partial v}{\partial t}+R_{1} G_{1} v $$ What can you discover about the solutions of this equation? Show that the characteristic impedance for monochromatic waves is $$ \breve{Z}_{0}=\left(\frac{R_{1}+j \omega L_{1}}{G_{1}+j \omega C_{1}}\right)^{1 / 2} $$

Consider a plasma of electron density \(n\) immersed in a uniform static magnetic field \(\mathbf{B}_{0 .}\) Let \(\mathbf{B}_{0}\) be in the \(z\) direction. Revise the equation of motion (8.8.2) to include the Lorentz force \(q\left(\mathbf{v} \times \mathbf{B}_{0}\right)\) on the electrons (but drop the collision term for simplicity); write out the resulting equation in cartesian components. (a) Show that plane waves propagating in the \(x\) direction, say, but with the electric field polarized parallel to \(\mathbf{B}_{0}\), are unaffected by the presence of \(\mathrm{B}_{0}\). (b) Show that circularly polarized plane waves (see Prob. \(8.3 .5\) ) can propagate in the \(z\) direction with wave numbers $$ K=\frac{\omega}{c}\left[1-\frac{\omega_{p}^{2}}{\omega\left(\omega \pm \omega_{b}\right)}\right]^{1 / 2} $$ where \(\omega_{b} \equiv c B_{0} / m\) is the cyclotron frequency. (c) Show that a TM wave can propagate in the \(x\) direction with the wave magnetic field polarized parallel to \(\mathbf{B}_{\theta}\), with the wave number $$ k=\frac{\omega}{c}\left[1-\frac{\omega_{p}^{2}\left(\omega^{2}-\omega_{p}^{2}\right)}{\omega^{2}\left(\omega^{2}-\omega_{p}^{2}-\omega_{b}^{2}\right)}\right]^{1 / 2} $$

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