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Chapter 5: Q37. (page 134)

A hypothetical planet has a mass 2.80 times that of Earth, but has the same radius. What is g near its surface?

Short Answer

Expert verified

The gravitational acceleration of the planet is 27.4m/s2.

Step by step solution

01

Step 1. Given Data

The mass of the planet is mp=2.80me.

02

Step 2. Understanding the acceleration due to gravity

In this problem, the equation of acceleration due to gravity at any location will be applied. Also, the value of mass as well as radius of the Earth will be used.

03

Step 3. Estimating the acceleration due to gravity on the planet

The relation of acceleration due to gravityis given by,

gp=Gmpr2

Here, G is the gravitational constant and ris the radius of the planet whose value is same as radius of the Earth.

On plugging the values in the above relation.

gp=G2.80mer2gp=2.80ggp=2.809.80m/s2gp=27.4m/s2

Thus, gp=27.4m/s2is the required acceleration due to gravity.

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