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Chapter 2: Q1. (page 43)

If you are driving at 95 km/h along a straight road, and you look to the side for 2.0 s, how far do you travel during this inattentive period?

Short Answer

Expert verified

You travel 52.78 m during the inattentive period.

Step by step solution

01

Step 1. Relation between the traveled distance with speed and time

The term ‘distance’ can be defined as the length measured in between any two given points. The distance covered by an object can be calculated by the product of the velocity of the object and the time taken to move from one point to another.

Given data.

The speed of the car is v=95kmh.

The inattentive duration of time is localid="1642739142775" Δt=2.0s.

Unit conversion.

v=95kmh=95kmh×1000m1km×1h3600s=26.39ms

Rule.

You know that

localid="1642739159913" Traveleddistance=speed×time=v×Δt…(i)

02

Step 2. Determination of the traveled distance during an inattentive period

Now, substituting all the values in equation (i), you will get

Traveleddistance=26.39ms×2.0s=52.78m

Therefore, you travel 52.78 m during the inattentive period.

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Most popular questions from this chapter

In the design of a rapid transit system, it is necessary to balance the average speed of a train against the distance between station stops. The more stops there are, the slower the train’s average speed. To get an idea of this problem, calculate the time it takes a train to make a 15.0-km trip in two situations: (a) the stations at which the trains must stop are 3.0 km apart (a total of 6 stations, including those at the ends); and (b) the stations are 5.0 km apart (4 stations total). Assume that at each station the train accelerates at a rate of1.1m/s2until it reaches95km/h, then stays at this speed until its brakes are applied for arrival at the next station, at which time it decelerates at2m/s2. Assume it stops at each intermediate station for 22 s.

At time t=0an object is travelling to the right along the + x axis at a speed of10m/s with acceleration -2.0m/s2. Which statement is true?

  1. The object will slow down, eventually coming to a complete stop.
  2. The object cannot have a negative acceleration and be moving to the right.
  3. The object will continue to move to the right, slowing down but never coming to a complete stop.
  4. The object will slow down, momentarily stopping, then pick up speed moving to the left.

A runner hopes to complete the 10,000-m run in less than 30.0 min. After running at constant speed for exactly 27.0 min, there are still 1200 m to go. The runner must then accelerate at0.20ms-2for how many seconds in order to achieve the desired time?

An airplane travels 2100 km at a speed of 720 km/h and then encounters a tailwind that boosts its speed to 990 km/h for the next 2800 km. What was the total time for the trip? What was the average speed of the plane for this trip?

[Hint: Does Eq. 2–11d apply?]

A baseball is hit almost straight up into the air with a speed of25ms-1. Estimate (a) how high it goes and (b) how long it is in the air. (c) What factors make this an estimate?
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