A rolling ball moves from x1=8.4cm tox2=-4.2cm during the time fromt1=3.0s to t2=6.1s. What is its average velocity over this time interval?

Short Answer

Expert verified

The average velocity over the time interval is -4.1cms.

Step by step solution

01

Step 1. Relation between average velocity, positions, and time

The term ‘average velocity’ can be defined as the division of the change in the displacement of a body from one point to another by the time taken in the displacement. It can also be defined as the average displacement divided by the average time taken by an object or a body.

Given data.

The initial position is x1=8.4cm.

The final position is x2=-4.2cm.

The initial time is t1=3.0s.

The final time is t2=6.1s.

We know that Averagevelocity=finalposition-initialpositiontimeelapsed.

02

Step 2. Calculation of average velocity using given values

Substituting the values in the above equation,

Averagevelocity=finalposition-initialpositiontimeelapsedv=x2-x1t2-t1=-4.2cm-8.4cm6.1s-3.0s=-4.1cms

Therefore, the average velocity over the time interval is -4.1cms.

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