In Fig. 2-44, (a) during what time periods, if any, is the velocity constant? (b) At what time is the velocity greatest? (c) At what time, if any, is the velocity zero? (d) Does the object move in one direction or in both directions during the time shown?

Figure 2-44 Problems 57,58 and 59

Short Answer

Expert verified

(a) The velocity of the object is constant between the time periods t = 0 s and t = 22 s.

(b) The velocity of the object is the greatest between 22 s and 29 s.

(c) The velocity of the object is zero at t = 37 s.

(d) The object moves in both directions during the time shown in the graph.

Step by step solution

01

Step 1. Position-time graph

The graph plotted between the position of an object and the time taken is referred to as the position-time graph. You can measure the velocity with the help of this graph. The slope of the position-time graph at any point gives the velocity of the object at that point.

02

Step 2. (a) Determination of the time period where the velocity is constant 

The velocity of an object is constant, where the slope of the position-time graph is constant. It is equivalent to the time period in which the position of the object varies at a constant rate with respect to time.

The graph is straight from t = 0 s to t = 22 s, approximately. Thus, the slope of the graph and the velocity of the object are constant between t = 0 s and t = 22 s.

03

Step 3. (b) Determination of the time at which velocity is greatest 

The slope of the position-time graph gives the velocity. The velocity of an object is the greatest when the positive slope of the graph is the largest (or steepest).

The slope of the given graph is the steepest between 22s and 29s. Thus, in this duration, the velocity of the object is the greatest.

04

Step 4. (c) Determination of the time at which velocity is zero

The velocity of an object is zero when the position-time graph is parallel to the time axis, i.e.,whentheposition of the object does not change with time.

The graph is at its peak between 35 s and 40 s. In this time interval, the velocity of the object becomes zero for a moment at the peak as the tangent to the graph for this duration becomes parallel to the time axis.

Thus, the velocity of the rabbit is zero at t = 37 s.

05

Step 5. (d) Determination of the direction of movement of the object  

The slope of the graph remains positive up to t= 37 s and becomes negative after this time. The displacement of the object increases till it reaches approximately 20 m at t= 37 s and then decreases. Therefore, the object moves in both directions and changes its direction after t= 37 s.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A car traveling at 95 km/h is 210 m behind a truck traveling at 75 km/h. How long will it take for the car to reach the truck?

A baseball is hit almost straight up into the air with a speed of25ms-1. Estimate (a) how high it goes and (b) how long it is in the air. (c) What factors make this an estimate?

At time t=0an object is travelling to the right along the + x axis at a speed of10m/s with acceleration -2.0m/s2. Which statement is true?

  1. The object will slow down, eventually coming to a complete stop.
  2. The object cannot have a negative acceleration and be moving to the right.
  3. The object will continue to move to the right, slowing down but never coming to a complete stop.
  4. The object will slow down, momentarily stopping, then pick up speed moving to the left.

Suppose you adjust your garden hose nozzle for a fast stream of water. You point the nozzle vertically upward at the height of 1.8 m above the ground (Fig. 2–40). When you quickly turn off the nozzle, you hear the water striking the ground next to you for another 2.5 s. What is the water speed as it leaves the nozzle?

Consider the street pattern shown in Fig. 2–46. Each inter-section has a traffic signal, and the speed limit is 40 km/h. Suppose you are driving from the west at the speed limit. When you are 10.0 m from the first intersection, all the lights turn green. The lights are green for 13.0 s each. (a) Calculate the time needed to reach the third stoplight. Can you make it through all three lights without stopping? (b) Another car was stopped at the first light when all the lights turned green. It can accelerate at the rate of2.00m/s2to the speed limit. Can the second car make it through all three lights without stopping? By how many seconds would it make it, or not make it?

FIGURE 2-46Problem 65

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free