Matt, in the foreground of Fig. 4-39, is able to move the large truck because

(a) he is stronger than the truck.

(b) he is heavier in some respect than the truck.

(c) he exerts a greater force on the truck than the truck exerts on him.

(d) the ground exerts greater friction on Matt than it does on the truck.

(e) the truck offers no resistance because its brakes are off.

Short Answer

Expert verified

The correct option is (d).

Step by step solution

01

Step 1. Action of various forces on Matt and the truck

Given data:

If the truck and Math both want to move forward, the friction force acts in the backward directionon both of them.

The forward force on Matt is equal to the force of friction on Matt.

The backward force on Matt is the tension of the cable between Matt and the truck.

Assumption:

Let the force on Matt by the truck and the force on the truck by Matt be the tension force on the cable.

02

Step 2. Condition to move the truck

When the truck is not moving, the cable's tension is equal to the friction force acting on the truck.

When the large truck moves, the tension is greater than the force of friction on the truck.

Also, this time Matt is moving, and the force on Matt is greater than the cable's tension.

Therefore, the ground exerts a greater friction force on Matt than it does on the truck.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Figure 4–53 shows a block (mass mA) on a smooth horizontal surface, connected by a thin cord that passes over a pulley to a second block (mB), which hangs vertically. (a) Draw a free-body diagram for each block, showing the force of gravity on each, the force (tension) exerted by the cord, and any normal force. (b) Apply Newton’s second law to find the formulas for the acceleration of the system and the tension in the cord. Ignore the friction and the masses of the pulley and the cord.

FIGURE 4-53 Problems 32 and 33. Mass mA rests on a smooth horizontal surface; mB hangs vertically.

One 3.2-kg paint bucket is hanging by a massless cord from another 3.2-kg paint bucket, also hanging by a massless cord, as shown in Fig. 4–49. (a) If the buckets are at rest, what is the tension in each cord? (b) If the two buckets are pulled upward with an acceleration of by the upper cord, calculate the tension in each cord.

A heavy crate rests on the bed of a flatbed truck. When the truck accelerates, the crate stays fixed on the truck, so it, too, accelerates. What force causes the crate to accelerate?

A child on a sled reaches the bottom of a hill with a velocity of10.0m/sand travels 25.0 m along a horizontal straightaway to a stop. If the child and sled together have a mass of 60.0 kg, what is the average retarding force on the sled on the horizontal straightaway?

What is the weight of a 68-kg astronaut (a) on Earth, (b) on the Moong=1.7m/s2(c) on Marsg=3.7m/s2(d) in outer space traveling with constant velocity?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free