(a) Why do you push down harder on the pedals of a bicycle when first starting out than when moving at a constant speed? (b) Why do you need to pedal at all when the cycle is at a constant speed?

Short Answer

Expert verified

(a) A person needs to push down harder on the pedals initially to overcome the inertia of the bicycle and the person and the frictional forces.

(b) A person needs to pedal while cycling at a constant speed because of the air resistance and frictional forces.

Step by step solution

01

Step 1. Newton’s first law

By Newton's first law of motion, every particle remains in a situation of rest or uniform motion except when constrained by an external force.

02

Step 2. Application of Newton’s first law

(a)

The bicycle is initially at rest. The inertia of the bicycle and the person must be overcome to start on the bicycle. Also, the static frictional force must be overcome. So, a strong force is required to overcome the inertia and frictional forces.

Therefore, a person needs to push harder on the pedals while starting on a bicycle.

03

Step 3. Application of Newton’s second law

(b)

The net force acting on an object moving with a constant speed is zero. Hence, the net force on the bicycle when it is moving at a constant speed is zero. However, frictional force and air resistance are present. The bicycle slows down and eventually comes to rest due to these forces if it is not pedaled.

Therefore, the bicycle needs to be pedaled even when it is moving at a constant speed.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 50-N crate sits on a horizontal floor where the coefficient of static friction between the crate and the floor is 0.50. A 20-N force is applied to the crate acting to the right. What is the resulting static friction force acting on the crate?

(a) 20 N to the right.

(b) 20 N to the left.

(c) 25 N to the right.

(d) 25 N to the left.

(e) None of the above; the crate starts to move.

According to a simplified model of a mammalian heart, at each pulse approximately 20 g of blood is accelerated from0.25m/sto0.35m/sduring a period of 0.10 s. What is the magnitude of the force exerted by the heart muscle?

To pull an old stump out of the ground, you and a friend tie two ropes to the stump. You pull on it with a force of 500 N to the north while your friend pulls with a force of 450 N to the northwest. The total force from the two ropes is

(a) less than 950 N.

(b) exactly 950 N.

(c) more than 950 N.

A stone hangs by a fine thread from the ceiling, and a section of the same thread dangles from the bottom of the stone (Fig. 4–36). If a person gives a sharp pull on the dangling thread, where is the thread likely to break: below the stone or above it? What if the person gives a slow and steady pull? Explain your answers.

FIGURE 4-36 Question 9

A small box is held in place against a rough vertical wall by someone pushing on it with a force directed upward at 28° above the horizontal. The coefficients of static and kinetic friction between the box and wall are 0.40 and 0.30, respectively. The box slides down unless the applied force has magnitude 23 N. What is the mass of the box?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free