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Chapter 16: Q5Q (page 443)

A positively charged rod is brought close to a neutral piece of paper, which it attracts. Draw a diagram showing the separation of charge in the paper and explain why attraction occurs.

Short Answer

Expert verified

The attraction is due to the generation of the electrostatic force.

Step by step solution

01

Concepts used in the solution

The same charge repels and the opposite charge attracts.

The positively charged rod creates a polarization of charge in the paper.

02

Explanation for the transfer of the charge

When the positively charged rod is near the piece of paper, it attracts the paper because the distance between the opposite charges is less, and the distance of the same charge is more after the polarization of charge in the piece of paper.

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Most popular questions from this chapter

When a charged ruler attracts small pieces of paper, sometimes a piece jumps quickly away after touching the ruler. Explain.

A point charge of mass 0.185 kg, and net charge\( + {\bf{0}}{\bf{.340 }}\mu {\bf{C}}\)hangs at rest at the end of an insulating cord above a large sheet of charge. The horizontal sheet of fixed uniform charge creates a uniform vertical electric field in the vicinity of the point charge. The tension in the cord is measured to be 5.18 N. Calculate the magnitude and direction of the electric field due to the sheet of charge (Fig. 16–67).

FIGURE 16–67 Problem 61.

(II) Two point charges, \({{\bf{Q}}_{\bf{1}}}{\bf{ = - 32}}\;{\bf{\mu C}}\) and \({{\bf{Q}}_{\bf{2}}}{\bf{ = + 45}}\;{\bf{\mu C}}\) are separated by a distance of 12 cm. The electric field at point P (see Fig. 16–57) is zero. How far from \({{\bf{Q}}_{\bf{1}}}\) is P?

In a simple model of the hydrogen atom, the electron revolves in a circular orbit around the proton with a speed of \({\bf{2}}{\bf{.2 \times 1}}{{\bf{0}}^{\bf{6}}}\;{\bf{m/s}}\). Determine the radius of the electron’s orbit. (Hint: See Chapter 5 on circular motion.)

A point charge \(\left( {m = 1.0 gram} \right)\) at the end of an insulating cord of length 55 cm is observed to be in equilibrium in a uniform horizontal electric field of \(9500 N/C\), when the pendulum’s position is as shown in Fig. 16–66, with the charge 12 cm above the lowest (vertical) position. If the field points to the right in Fig. 16–66, determine the magnitude and sign of the point charge.

FIGURE 16–66 Problem 57.
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