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Chapter 16: Q6Q (page 443)
Contrast the net charge on a conductor to the “free charges” in the conductor.
The net charge equals the sum of all positive and negative charges in the conductor.
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(II) A charge of 6.15 mC is placed at each corner of a square 0.100 m on a side. Determine the magnitude and direction of the force on each charge.
(I) A proton is released in a uniform electric field, and it experiences an electric force of\({\bf{1}}{\bf{.86}} \times {\bf{1}}{{\bf{0}}^{ - {\bf{14}}}}{\bf{ N}}\)toward the south. Find the magnitude and direction of the electric field.
A proton \(\left( {m = 1.67 \times 1{0^{ - 27}} kg} \right)\) is suspended at rest in a uniform electric field \(\overrightarrow {\bf{E}} \). Take into account gravity at the Earth’s surface, and determine \(\overrightarrow {\bf{E}} \).
Consider the electric field at the three points indicated by the letters A, B, and C in Fig. 16–49. First draw an arrow at each point indicating the direction of the net force that a positive test charge would experience if placed at that point, then list the letters in order of decreasing field strength (strongest first). Explain.
Figure 16–50 shows electric field lines due to a point charge. What can you say about the field at point 1 compared with the field at point 2?
(a) The field at point 2 is larger, because point 2 is on a field line.
(b) The field at point 1 is larger, because point 1 is not on a field line.
(c) The field at point 1 is zero, because point 1 is not on a field line.
(d) The field at point 1 is larger, because the field lines are closer together in that region.
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