Chapter 16: Q6Q (page 443)
Contrast the net charge on a conductor to the “free charges” in the conductor.
Short Answer
The net charge equals the sum of all positive and negative charges in the conductor.
Chapter 16: Q6Q (page 443)
Contrast the net charge on a conductor to the “free charges” in the conductor.
The net charge equals the sum of all positive and negative charges in the conductor.
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(III) A point charge Q rests at the center of an uncharged thin spherical conducting shell. (See Fig. 16–34.) What is the electric field E as a function of r (a) for r less than the inner radius of the shell, (b) inside the shell, and (c) beyond the shell? (d) How does the shell affect the field due to Q alone? How does the charge Q affect the shell?

The form of Coulomb’s law is very similar to that for Newton’s law of universal gravitation. What are the differences between these two laws? Compare also gravitational mass and electric charge.
A point charge \(\left( {m = 1.0 gram} \right)\) at the end of an insulating cord of length 55 cm is observed to be in equilibrium in a uniform horizontal electric field of \(9500 N/C\), when the pendulum’s position is as shown in Fig. 16–66, with the charge 12 cm above the lowest (vertical) position. If the field points to the right in Fig. 16–66, determine the magnitude and sign of the point charge.

FIGURE 16–66 Problem 57.
Figure 16–50 shows electric field lines due to a point charge. What can you say about the field at point 1 compared with the field at point 2?
(a) The field at point 2 is larger, because point 2 is on a field line.
(b) The field at point 1 is larger, because point 1 is not on a field line.
(c) The field at point 1 is zero, because point 1 is not on a field line.
(d) The field at point 1 is larger, because the field lines are closer together in that region.

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