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Chapter 10: Q19P (page 260)

(II) How high would the atmosphere extend if it were of uniform density throughout, equal to half the present density at sea level?

Short Answer

Expert verified

The height of the atmosphere is double the present height.

Step by step solution

01

Concepts of fluid pressure

In this problem, for calculating the extent of the atmosphere the relation of fluid pressure is used.

02

Calculation of height

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Most popular questions from this chapter

A submerged can of Coke sink, but a can of Diet Coke will float. (Try it!) Explain.

In Fig. 10-54, take into account the speed of the top surface of the tank and show that the speed of fluid leaving an opening near the bottom is \({{\bf{v}}_{\bf{1}}}{\bf{ = }}\sqrt {\frac{{{\bf{2gh}}}}{{\left( {{\bf{1 - A}}_{\bf{1}}^{\bf{2}}{\bf{/A}}_{\bf{2}}^{\bf{2}}} \right)}}} \),

where \({\bf{h = }}{{\bf{y}}_{\bf{2}}} - {{\bf{y}}_{\bf{1}}}\), and \({{\bf{A}}_{\bf{1}}}\) and \({{\bf{A}}_{\bf{2}}}\) are the areas of the opening and of the top surface, respectively. Assume \({{\bf{A}}_{\bf{1}}}{\bf{ < < }}{{\bf{A}}_{\bf{2}}}\) so that the flow remains nearly steady and laminar.

Figure 10-54

An object that can float in both water and in oil (whose density is less than that ofwater) experiences a buoyant force that is

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