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Chapter 10: Q19P (page 260)

(II) How high would the atmosphere extend if it were of uniform density throughout, equal to half the present density at sea level?

Short Answer

Expert verified

The height of the atmosphere is double the present height.

Step by step solution

01

Concepts of fluid pressure

In this problem, for calculating the extent of the atmosphere the relation of fluid pressure is used.

02

Calculation of height

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Most popular questions from this chapter

Estimate the difference in air pressure between the top and the bottom of the Empire State Building in New York City. It is 380 m tall and is located at sea level. Express as a fraction of atmospheric pressure at sea level.

Water at a gauge pressure of \({\bf{3}}{\bf{.8}}\;{\bf{atm}}\) at street level flows into an office building at a speed of \({\bf{0}}{\bf{.78}}\;{\bf{m/s}}\) through a pipe \({\bf{5}}{\bf{.0}}\;{\bf{cm}}\)in diameter. The pipe tapers down to \({\bf{2}}{\bf{.8}}\;{\bf{cm}}\) in diameter by the top floor, \({\bf{16}}\;{\bf{m}}\) above (Fig. 10–53), where the faucet has been left open. Calculate the flow velocity and the gauge pressure in the pipe on the top floor. Assume no branch pipes and ignore viscosity.

Figure 10-53

(I) State your mass and then estimate your volume. [Hint: Because you can swim on or just under the surface of the water in a swimming pool, you have a pretty good idea of your density.

(I)Show that Bernoulli’s equation reduces to the hydrostatic variation of pressure with depth (Eq. 10-3b) when there is no flow\(\left( {{v_1} = {v_2} = 0} \right)\).

Beaker A is filled to the brim with water. Beaker B is the same size and contains a small block of wood that floats when the beaker is filled with water to the brim. Which beaker weighs more?

(a) Beaker A.

(b) Beaker B.

(c) The same for both

See all solutions

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