Chapter 7: Q1P (page 170)
(I) What is the magnitude of the momentum of a 28-g sparrow flying with a speed of 8.4 m/s?
Short Answer
The magnitude of the momentum of the sparrow is \(0.24\;{\rm{kg}} \cdot {\rm{m/s}}\;\).
Chapter 7: Q1P (page 170)
(I) What is the magnitude of the momentum of a 28-g sparrow flying with a speed of 8.4 m/s?
The magnitude of the momentum of the sparrow is \(0.24\;{\rm{kg}} \cdot {\rm{m/s}}\;\).
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The masses of the Earth and Moon are \({\bf{5}}{\bf{.98 \times 1}}{{\bf{0}}^{{\bf{24}}}}\;{\bf{kg}}\) and \({\bf{7}}{\bf{.35 \times 1}}{{\bf{0}}^{{\bf{22}}}}\;{\bf{kg}}\), respectively, and their centers are separated by \({\bf{3}}{\bf{.84 \times 1}}{{\bf{0}}^{\bf{8}}}\;{\bf{m}}\).
(a) Where is the CM of the Earth–Moon system located?
(b) What can you say about the motion of the Earth–Moon system about the Sun, and of the Earth and Moon separately about the Sun?
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A bullet of mass \(m{\bf{ = 0}}{\bf{.0010}}\;{\bf{kg}}\) embeds itself in a wooden block with mass \(M{\bf{ = 0}}{\bf{.999}}\;{\bf{kg}}\), which then compresses a spring \(\left( {k{\bf{ = 140}}\;{\bf{N/m}}} \right)\) by a distance \(x{\bf{ = 0}}{\bf{.050}}\;{\bf{m}}\) before coming to rest. The coefficient of kinetic friction between the block and table is \(\mu {\bf{ = 0}}{\bf{.50}}\).
(a) What is the initial velocity (assumed horizontal) of the bullet?
(b) What fraction of the bullet's initial kinetic energy is dissipated (in damage to the wooden block, rising temperature, etc.) in the collision between the bullet and the block?
An atomic nucleus of mass m traveling with speed v collides elastically with a target particle of mass 2m (initially at rest) and is scattered at 90°.
(a) At what angle does the target particle move after the collision?
(b) What are the final speeds of the two particles?
(c) What fraction of the initial kinetic energy is transferred to the target particle?
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