(I) The distance between a carbon atom \(\left( {{\bf{m = 12}}\;{\bf{u}}} \right)\) and an oxygen atom \(\left( {{\bf{m = 16}}\;{\bf{u}}} \right)\) in the CO molecule is \({\bf{1}}{\bf{.13 \times 1}}{{\bf{0}}^{{\bf{10}}}}\;{\bf{m}}\) How far from the carbon atom is the center of mass of the molecule?

Short Answer

Expert verified

The center of mass of the CO atom is at a distance of \(6.46 \times {10^{ - 11}}\;{\rm{m}}\) from the carbon atom.

Step by step solution

01

Given data

The center of mass is near the heavy atom for a two-atom system.

The mass of the carbon atom is \({m_1} = 12\;{\rm{u}}\).

The mass of the oxygen atom is \({m_2} = 16\;{\rm{u}}\).

The distance between the atoms is \(r = 1.13 \times {10^{ - 10}}\;{\rm{m}}\).

Let the carbon atom be at the origin, and the oxygen atom at \(r\).

02

Calculation of the center of mass

Now, the center of mass of the CO atom is:

\(\begin{array}{c}{x_{{\rm{CM}}}} = \frac{{\left( {{m_1} \times 0} \right) + \left( {{m_2} \times r} \right)}}{{{m_1} + {m_2}}}\\ = \frac{{\left( {12\;{\rm{u}} \times 0} \right) + \left( {16\;{\rm{u}} \times 1.13 \times {{10}^{ - 10}}\;{\rm{m}}} \right)}}{{12\;{\rm{u}} + 16\;{\rm{u}}}}\\ = 6.46 \times {10^{ - 11}}\;{\rm{m}}\end{array}\)

Hence, the center of mass of the CO atom is at a distance of \(6.46 \times {10^{ - 11}}\;{\rm{m}}\) from the carbon atom.

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