Question: (I) A certain dog whistle operates at 23.5 kHz, while another (brand X) operates at an unknown frequency. If humans can hear neither whistle when played separately, but a shrill whine of frequency 5000 Hz occurs when they are played simultaneously, estimate the operating frequency of brand X.

Short Answer

Expert verified

The operating frequency of brand X is \(28.5\;{\rm{kHz}}\).

Step by step solution

01

Determination of the operating frequency

The operating frequency of brand X value can be obtained by using the beat frequency formula, which is equal to the difference of two different wave frequencies.

02

Given information

Given data:

The frequency of dog whistle is \({f_1} = 23.5\;{\rm{kHz}}\).

The beat frequency is \({f_B} = 5000\;{\rm{Hz}}\).

03

Evaluation of operating frequency of brand X

The operating frequency of brand X can be calculated as:

\(\begin{array}{c}{f_B} = \left| {{f_2} - {f_1}} \right|\\\left( {5000\;{\rm{Hz}} \times \frac{{{{10}^{ - 3}}\;{\rm{kHz}}}}{{1\;{\rm{Hz}}}}} \right) = \left| {{f_2} - \left( {23.5\;{\rm{kHz}}} \right)} \right|\\{f_2} = 28.5\;{\rm{kHz}}\end{array}\)

Thus, the operating frequency of brand X is \(28.5\;{\rm{kHz}}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A guitar string vibrates at a frequency of 330 Hz with a wavelength 1.40 m. The frequency and wavelength of this sound in air (20°C) as it reaches our ears is

(a) same frequency, same wavelength.

(b) higher frequency, same wavelength.

(c) lower frequency, same wavelength.

(d) same frequency, longer wavelength.

(e) same frequency, shorter wavelength.

Traditional methods of protecting the hearing of people who work in areas with very high noise levels have consisted mainly of efforts to block or reduce noise levels. With a relatively new technology, headphones are worn that do not block the ambient noise. Instead, a device is used which detects the noise, inverts it electronically, then feeds it to the headphones in addition to the ambient noise. How could adding more noise reduce the sound levels reaching the ears?

Question: (II) Approximately what are the intensities of the first two overtones of a violin compared to the fundamental? How many decibels softer than the fundamental are the first and second overtones? (See Fig. 12–15.)

You look directly overhead and see a plane exactly 1.45 km above the ground flying faster than the speed of sound. By the time you hear the sonic boom, the plane has traveled a horizontal distance of 2.0 km. See Fig. 12-38. Determine (a) the angle of the shock cone, \(\theta \), and (b) the speed of the plane and its Mach number. Assume the speed of sound is 330 m/s.

How far from the mouthpiece of the flute in Example 12–11 should the hole be that must be uncovered to play \({\bf{F}}\) above middle \({\bf{C}}\) at \({\bf{349}}\;{\bf{Hz}}\)?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free