A shop sign weighing 215 N hangs from the end of a uniform 155-N beam, as shown in Fig. 9–58. Find the tension in the supporting wire (at 35.0°) and the horizontal and vertical forces exerted by the hinge on the beam at the wall. [Hint: First, draw a free-body diagram

Short Answer

Expert verified

The tension in the supporting wire is 642.2 N.

The horizontal and vertical components of the forces by the hinge are \(526.1\;{\rm{N}}\) and \(1.6\;{\rm{N}}\), respectively.

Step by step solution

01

Concepts

In equilibrium, the net force in the x and y directions should be zero, and the torque about any point is zero.For this problem, you can calculate the tension in the wire using the condition for the zero torque about the hinge.

02

Given data

The weight of the shop sign is \({W_1} = 215\;{\rm{N}}\).

The weight of the beam is \({W_2} = 155\;{\rm{N}}\).

The angle of the wire is \(\theta = {35.0^ \circ }\).

The length of the beam is \({L_1} = 1.70\;{\rm{m}}\).

The supported wire is attached at a distance of \({L_2} = 1.35\;{\rm{m}}\) from the hinge.

You can assume that the mass of the beam is in the middle of the beam.

Let \({F_{\rm{x}}}\) and \({F_{\rm{y}}}\) be the horizontal and vertical components of the forces exerted by the hinge on the beam.

03

Calculation of the tension

The torque about the hinge is

\(\begin{array}{c}T\sin \theta \times {L_2} - {W_1}{L_1} - {W_2}\frac{{{L_1}}}{2} = 0\\T\sin \theta \times {L_2} = \left( {{W_1} + \frac{{{W_2}}}{2}} \right){L_1}\\T \times \sin {35.0^ \circ } \times 1.35\;{\rm{m}} = \left( {215\;{\rm{N}} + \frac{{155\;{\rm{N}}}}{2}} \right)1.70\;{\rm{m}}\\T = 642.2\;{\rm{N}}\end{array}\).

Hence, the tension in the supporting wire is 642.2 N.

04

Calculation of the force by the hinge

Now, the condition for the horizontal forces at equilibrium is

\(\begin{array}{c}{F_{\rm{x}}} = T\cos \theta \\ = \left( {642.2\;{\rm{N}}} \right) \times \cos {35.0^ \circ }\\ = 526.1\;{\rm{N}}\end{array}\).

Now, the condition for the vertical forces at equilibrium is

\(\begin{array}{c}{F_{\rm{y}}} + T\sin \theta = {W_1} + {W_2}\\{F_{\rm{y}}} + \left[ {\left( {642.2\;{\rm{N}}} \right) \times \sin {{35.0}^ \circ }} \right] = 215\;{\rm{N}} + 155\;{\rm{N}}\\{F_{\rm{y}}} = 1.6\;{\rm{N}}\end{array}\).

Hence, the horizontal and vertical components of the forces by the hinge are \(526.1\;{\rm{N}}\) and \(1.6\;{\rm{N}}\), respectively.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A parking garage is designed for two levels of cars. To make more money, the owner decides to double the size of the garage in each dimension (length, width, and the number of levels). For the support columns to hold up four floors instead of two, how should he change the columns' diameter?

(a) Double the area of the columns by increasing their diameters by a factor of 2

(b) Double the area of the columns by increasing their diameters by a factor of \(\sqrt 2 \)

(c) Quadruple the area of the columns by increasing their diameters by a factor of 2

(d) Increase the area of the columns by a factor of 8 by increasing their diameters by a factor of \(2\sqrt 2 \)

(e) He doesn't need to increase the diameter of the columns

(III) Two wires run from the top of a pole 2.6 m tall that supports volleyball net. The two wires are anchored to the ground 2.0 m apart, and each is 2.0 m from the pole (Fig. 9–66). The tension in each wire is 115 N. What is the tension in the net, assumed horizontal and attached at the top of the pole?

(I) Approximately what magnitude force, \({F_{\bf{M}}}\)must the extensor muscle in the upper arm exert on the lower arm to hold a 7.3-kg shot put (Fig. 9–71)? Assume the lower arm has a mass of 2.3 kg and its CG is 12.0 cm from the elbow-joint pivot.

(II) (a) Calculate the magnitude of the force, required of the “deltoid” muscle to hold up the outstretched arm shown in Fig. 9–72. The total mass of the arm is 3.3 kg. (b) Calculate the magnitude of the force exerted by the shoulder joint on the upper arm and the angle (to the horizontal) at which it acts.

(III) A uniform ladder of mass mand length leans at an angle\(\theta \)against a frictionless wall, Fig. 9–70. If the coefficient of static friction between the ladder and the ground is\({\mu _s}\). Determine a formula for the minimum angle at which the ladder will not slip.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free