A heavy ball suspended by a cable is pulled to the side by a horizontal force \(\vec F\), as shown in Fig. 9–43. If angle \(\theta \) is small, the magnitude of the force F can be less than the weight of the ball because

(a) the force holds up only part of the ball’s weight.

(b) even though the ball is stationary, it is not really in equilibrium.

(c) \(\vec F\) is equal to only the x component of the tension in the cable.

(d) the original statement is not true. To move the ball, \(\vec F\) must be at least equal to the ball’s weight.

Short Answer

Expert verified

The correct option is (c).

Step by step solution

01

Concepts

At equilibrium, the net force is zero.For this problem, the horizontal and vertical forces balance each other for the equilibrium of the ball.

02

Explanation

Let m be the mass of the ball and T be the tension in the cable. The cable makes \(\theta \) angle with the vertical.

Condition for equilibrium:

For the horizontal forces, the magnitude of the force is equal to the x component of the tension force.

For the vertical force, the weight is equal to the y component of the tension force.

Hence, option (c) is correct.

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