Why do you tend to lean backward when carrying a heavy load in your arms?

Short Answer

Expert verified

You lean backward to keep the center of mass over your feet.

Step by step solution

01

Understanding center of mass

In this problem, the concept of center of mass will be used. The center of mass is the point on a component at which the total mass is concentrated.

02

Explanation for the backward movement of a body due to heavy load

When a particular person is carrying a heavy load, his/her body tends to move backward in order to maintain the center of mass of the body over the feet. If the center of mass of the body is in front of the feet, the person will fall forward.

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Most popular questions from this chapter

(I) By how much is the column in Problem 41 shortened if it is 8.6 m high?

(I) A tower crane (Fig. 9–48a) must always be carefully balanced so that there is no net torque tending to tip it. A particular crane at a building site is about to lift a 2800-kg air-conditioning unit. The crane’s dimensions are shown in Fig. 9–48b. (a) Where must the crane’s 9500-kg counterweight be placed when the load is lifted from the ground? (The counterweight is usually moved automatically via sensors and motors to precisely compensate for the load.) (b) Determine the maximum load that can be lifted with this counterweight when it is placed at its full extent. Ignore the mass of the beam.

\(4194.8\;{\rm{kg}}\)

(II) A 172-cm-tall person lies on a light (massless) board which is supported by two scales, one under the top of her head and one beneath the bottom of her feet (Fig. 9–64). The two scales read, respectively, 35.1 and 31.6 kg. What distance is the center of gravity of this person from the bottom of her feet?

A 25-kg object is being lifted by two people pulling on the ends of a 1.15-mm-diameter nylon cord that goes over two 3.00-m-high poles 4.0 m apart, as shown in Fig. 9–86. How high above the floor will the object be when the cord breaks?

(II) At depths of 2000 m in the sea, the pressure is about 200 times atmospheric pressure\(\left( {{{\bf{P}}_{\bf{a}}}{\bf{ = 1}}{\bf{.0 \times 1}}{{\bf{0}}^{\bf{5}}}\;{\bf{N/}}{{\bf{m}}^{\bf{2}}}} \right)\). By what percentage does the interior space of an iron bathysphere’s volume change at this depth?

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