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Chapter 13: Q3Q (page 359)

Question: Which is larger, 1 C° or 1 F? Explain why.

Short Answer

Expert verified

1 C° is larger than 1 F°.

Step by step solution

01

Understanding of temperature

The term "temperature" may be defined as the thermodynamical characteristic of a particular system, determining whether a body is cool or warm.

02

Relationship between the 1 C° and 1 F°

One hundred divisions on the centigrade scale are equal to the 180 divisions on the Fahrenheit scale. Therefore, the relationship between the centigrade and Fahrenheit can be written as follows:

\(\begin{array}{c}1{\rm{^\circ C}} = \frac{{180}}{{100}}\;{\rm{^\circ F}}\\1{\rm{^\circ C}} = \frac{9}{5}{\rm{^\circ F}}\\{\rm{1^\circ C}} = 1.8{\rm{^\circ F}}\end{array}\)

From the above relation, it is clear that the centigrade scale is larger than the Fahrenheit scale.

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Most popular questions from this chapter

Question: (II)Two isotopes of uranium,\({}^{{\bf{235}}}{\bf{U}}\)and\({}^{{\bf{238}}}{\bf{U}}\)(the superscripts refer to their atomic masses), can be separated by a gas diffusion process by combining them with fluorine to make the gaseous compound\({\bf{U}}{{\bf{F}}_{\bf{6}}}\). Calculate the ratio of the rms speeds of these molecules for the two isotopes, at constant T. Use Appendix B for masses.

Question 37:(III) An air bubble at the bottom of a lake 41.0 m deep has a volume of\({\bf{1}}{\bf{.00}}\;{\bf{c}}{{\bf{m}}^{\bf{3}}}\). If the temperature at the bottom is 5.5°C and at the top 18.5°C, what is the radius of the bubble just before it reaches the surface?

Question 14: Freezing a can of soda will cause its bottom and top to bulge

so badly the can will not stand up. What has happened?

(II) A storage tank at STP contains 28.5 kg of nitrogen \(\left( {{{\rm{N}}_{\rm{2}}}} \right)\). (a) What is the volume of the tank? (b) What is the pressure if an additional 32.2 kg of nitrogen is added without changing the temperature?

Question: (II)Show that for a mixture of two gases at the same temperature, the ratio of their rms speeds is equal to the inverse ratio of the square roots of their molecular masses,\(\frac{{{{\bf{v}}_{\bf{1}}}}}{{{{\bf{v}}_{\bf{2}}}}}{\bf{ = }}\sqrt {\frac{{{{\bf{M}}_{\bf{2}}}}}{{{{\bf{M}}_{\bf{1}}}}}} \).
See all solutions

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