Mammals that depend on being able to run fast have slender lower legs with flesh and muscle concentrated high, close to the body (Fig. 8–33). On the basis of rotational dynamics, explain why this distribution of mass is advantageous.

FIGURE 8-33 Question 6. A gazelle.

Short Answer

Expert verified

The distribution of mass of a gazelle will be advantageous for it because it can run faster with high angular acceleration for the same amount of torque.

Step by step solution

01

Understanding the variation of rotational inertia due to the distribution of mass in a gazelle

The distribution of mass in a gazelle is highly concentrated close to the body of the gazelle. The lower legs have fewer moments of inertia. So, less rotational inertia is required.

However, if the mass is uniformly distributed all over the body of a gazelle, the rotational inertia will be greater.

02

Understanding the distribution of mass of a gazelle

A gazelle’s body is designed in a manner such that the distribution of mass is on the higher side of the body. So, the moment of inertia is higher close to the body. However, the legs of the gazelle are slender lower. The legs have less distribution of mass. So, the moment of inertia of the legs is less. The rotational inertia of the legs is less.

03

Understanding the concept of rotational dynamics on the gazelle

For the same amount of angular acceleration, the gazelle requires less torque to run. Similarly, for the same amount of torque, the gazelle will run faster with high angular acceleration.

Thus, the distribution of mass of a gazelle will be advantageous for it because it can run faster with high angular acceleration for the same amount of torque.

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Most popular questions from this chapter

Suppose a disk rotates at constant angular velocity. (a) Does a point on the rim have radial and or tangential acceleration? (b) If the disk’s angular velocity increases uniformly, does the point have radial and or tangential acceleration? (c) For which cases would the magnitude of either component of linear acceleration change?

(II) A roller-coaster car shown in Fig. 6–41 is pulled up to point 1 where it is released from rest. Assuming no friction, calculate the speed at points 2, 3, and 4.

FIGURE 6–41 Problem 40

A 125-kg astronaut (including space suit) acquires a speed of \({\bf{2}}{\bf{.50}}\;{{\bf{m}} \mathord{\left/{\vphantom {{\bf{m}} {\bf{s}}}} \right.\\} {\bf{s}}}\) by pushing off with her legs from a 1900-kg space capsule.

(a) What is the change in speed of the space capsule?

(b) If the push lasts 0.600 s, what is the average force exerted by each on the other? As the reference frame, use the position of the capsule before the push. (c) What is the kinetic energy of each after the push?

(III) A cyclist intends to cycle up a 7.50° hill whose vertical height is 125 m. The pedals turn in a circle of diameter 36.0 cm. Assuming the mass of bicycle plus person is 75.0 kg, (a) calculate how much work must be done against gravity. (b) If each complete revolution of the pedals moves the bike 5.10 m along its path, calculate the average force that must be exerted on the pedals tangent to their circular path. Neglect work done by friction and other losses.

A cubic crate of side\(s = 2.0\;{\rm{m}}\)is top-heavy: its CG is 18 cm above its true center. How steep an incline can the crate rest on without tipping over? [Hint: The normal force would act at the lowest corner].

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