Write the following as full (decimal) numbers without prefixes on the units: (a) 286.6 mm, (b) 85 μV(c) 760 mg, (d) 62.1 ps, (e) 22.5 nm, (f) 2.50 gigavolts.

Short Answer

Expert verified

The full decimal numbers without prefixes on the units for parts (a), (b), (c), (d), (e) and (f) are \(d = 0.2866\;{\rm{m}}\), .., \(m = 0.760\;{\rm{g}}\), \(t = 0.0000000000621\;{\rm{s}}\), \(l = 0.000000225\;{\rm{m}}\), and \(V = 2500000000\;{\rm{V}}\).

Step by step solution

01

Use of prefixes 

Prefix:

A prefix is a word that signifies the term added before a given word in order to alter its determination.For example, in the word supernatural, the word “super” is a prefix.

Metrix:

Metrix is a term that results from the measurement of quantitative assessment. In aspects such as comparing, assessment of metrics is important.

The full decimal number without a prefix on the unit is

\(\begin{aligned}{l}d = \left( {286.6\;{\rm{mm}} \times \frac{{1\;{\rm{m}}}}{{1000\;{\rm{mm}}}}} \right)\\ = 0.2866\;{\rm{m}}{\rm{.}}\end{aligned}\)

02

Use of Prefixes

The full decimal number without a prefix on the unit is

\(\begin{aligned}{l}V = \left( {85\;{\rm{\mu V}} \times \frac{{{{10}^{ - 6}}\;{\rm{V}}}}{{1\;{\rm{\mu V}}}}} \right)\\ = 0.000085\;{\rm{s}}{\rm{.}}\end{aligned}\)

03

Use of Prefixes

The full decimal number without a prefix on the unit is

\(\begin{aligned}{l}m = \left( {760\;{\rm{mg}} \times \frac{{{{10}^{ - 3}}\;{\rm{g}}}}{{1\;{\rm{mg}}}}} \right)\\ = 0.760\;{\rm{g}}{\rm{.}}\end{aligned}\)

04

Metrix (SI) Prefix

The full decimal number without a prefix on the unit is

\(\begin{aligned}{l}t = \left( {62.1\;{\rm{ps}} \times \frac{{{{10}^{ - 12}}\;{\rm{s}}}}{{1\;{\rm{ps}}}}} \right)\\ = 0.0000000000621\;{\rm{s}}{\rm{.}}\end{aligned}\)

05

SI Prefix

The full decimal number without a prefix on the unit is

\(\begin{aligned}{l}l = \left( {22.5\;{\rm{nm}} \times \frac{{{{10}^{ - 9}}\;{\rm{m}}}}{{1\;{\rm{nm}}}}} \right)\\ = 0.000000225\;{\rm{m}}{\rm{.}}\end{aligned}\)

06

SI Prefix

The full decimal number without a prefix on the unit is

\(\begin{aligned}{l}V = \left( {2.50\;{\rm{gV}} \times \frac{{{{10}^9}\;{\rm{V}}}}{{1\;{\rm{gV}}}}} \right)\\ = 2500000000\;{\rm{V}}{\rm{.}}\end{aligned}\)

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