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Chapter 6: Q38P (page 138)

Question: (I) The total electric flux from a cubical box of side 28.0 cm is.What charge is enclosed by the box?

Short Answer

Expert verified

The charge enclosed by the box is \(1.64 \times {10^{ - 8}}\;{\rm{C}}\).

Step by step solution

01

Determination of the enclosed charge value

The value of the enclosed charge can be calculated by multiplying the value of the electric flux with the value of the permittivity of free space.

02

Given information

Given data:

The length of the side of a cubical box is \(a = 28.0\;{\rm{cm}}\).

The total electric flux is

03

Evaluation of the charge enclosed by the box

The charge enclosed by the box can be calculated using the following expression:

\({Q_{{\rm{Enclosed}}}} = {\phi _{\rm{E}}}{\varepsilon _{\rm{o}}}\)

Here, \({\varepsilon _{\rm{o}}}\) is the permittivity of free space, and its value is

Substitute the values in the above equation.

Thus, the charge enclosed by the box is \(1.64 \times {10^{ - 8}}\;{\rm{C}}\).

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