Question: Workers around jet aircraft typically wear protective devices over their ears. Assume that the sound level of jet airplane engine, at a distance of 30 m, is 130 dB, and that the average human ear has an effective radius of 2.0 cm. What would be the power intercepted by an unprotected ear at a distance of 30 m from a jet airplane engine?

Short Answer

Expert verified

The power intercepted by the unprotected ear is \(0.013\;{\rm{W}}\).

Step by step solution

01

Step-1: Determinaton of power of engine

The intensity of sound is determined using the formula of sound level. The product of intensity and area gives the power intercepted.

02

Given Information

Given data:

The sound level of the jet engine is \(\beta = 130\;dB\).

The reference level intensity is \({I_0} = 1{0^{ - 12}}\) W/m2

The effective radius of ear is \(r = 2\;cm\).

03

Find the intensity received by unprotected ear

The intensity received by the unprotected ear can be calculated as:

04

Find the power intercepted by the unprotected ear

The power intercepted by the unprotected ear can be calculated as:

Thus, the power intercepted by the unprotected ear is \(0.013\;{\rm{W}}\).

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