Chapter 8: Problem 14
$$ \rho(k) d E_{k}=\left(\frac{L}{2 \pi}\right)^{3} k^{2} d k \sin \theta d \theta d \phi $$ Since \(E_{k}=\hbar^{2} k^{2} / 2 \mu, d E_{k} / d k=\hbar^{2} k / \mu\), and we obtain for \(\rho(k)\) $$ \rho(k)=\frac{\mu L^{3}}{8 \pi^{3} h^{2}} k \sin \theta d \theta d \phi $$
Short Answer
Expert verified
The expression for \(\rho(k)\) is \(\frac{\mu L^3 k}{8 \pi^3 \hbar^2} \sin \theta d\theta d\phi\).
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Key Concepts
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